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2 years ago

Jordan shoots 100 3-point shots per basketball practice.she makes 44 shots.what decimal represents the number of shots she makes

Mathematics

2 answers:

makvit [3.9K]2 years ago

5 0

0.44 shots is made (44/100)

-BARSIC- [3]2 years ago

5 0

Answer:

<h2>0.44 represents the number of shots she makes.</h2>

Step-by-step explanation:

Givens

Jordan shoots 100 3-points shots
She makes or succeed 44 shots.

"The decimal number that represents the number of shots she makes" refers to the ratio between succeed shots and total shots, which can be presented as a fraction, decimal or percentage. The ratio is

$\frac{44 \ scored}{100 \ total}=\frac{11}{25}=0.44 (or \ 44\%)$

Therefore, 0.44 represents the number of shots she makes.

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Susan is attending a talk at her son's school. There are 8 rows of 10chairs where 54 parents are sitting. Susan notices that eve

kozerog [31]

Answer:

The largest possible number of adjacent empty chairs in a single row is 3

Step-by-step explanation:

The parameters given are;

The number of chairs = 8 × 10 = 80 chairs

The number of parents = 54

Sitting arrangements of parents = Alone or to one other person

Therefore;

The maximum number of parents on a row = 1 + 1 + 0 + 1 + 1 + 0 + 1 + 1 + 0 + 1 = 7

Hence when the rows have the maximum number of parents occupying the seats we have for the 8 rows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 7 = 56

But there are only 54 parents, therefore, up to the 7th row will have 7 parents while the 8th row will have only 5 parents to make the possible sitting arrangement to be as follows;

7 + 7 + 7 + 7 + 7 + 7 + 7 + 5 = 54

The sitting arrangement for the 8th row is therefore

1 + 1 + 0 + 1 + 1 + 0 + 1 + 0 + 0 + 0

Hence there will be three empty seats in the 8th row making the largest possible number of adjacent empty chairs in a single row = 3.

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2 years ago

Assuming no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales b

alexira [117]

Answer:

Step-by-step explanation:

Given that we assume no direct factory overhead costs (i.e., inventory carry costs) and $3 million dollars in combined promotion and sales budget, the Deal product manager wishes to achieve a product contribution margin of 35%.

Sales - variable cost = Fixed cost + profit

Here fixed cost = 3 million dollars

Sales - variable = contribution = 35%

35% should atleast meet the fixed cost

i.e. 35% = 3 million

100% = 8.57 million can be cost

Since fixed cost will not change and remain 3 million these 5,57 million can be given to material and labor costs

So material and labor cost should be limited upto 5.57 million increase.

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2 years ago

Every morning, a deli offers a “commuter special” in which customers can select a pastry, beverage, and a copy of one of the loc

mars1129 [50]

To find the number of possible combinations, you multiple the possible number of outcomes for each category together. For example, there are 5 choices of pastries, 4 choices of drinks, and 2 newspaper choices, so normally there are 5 x 4 x 2=40 possible combinations. Without a muffin, these numbers would change to 4 x 4 x 2=32. The difference would be 8 possible options, so choice C.

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2 years ago

Read 2 more answers

What is equivalent to -3(3y-2x)+2(5x-4y)

aev [14]

-9y+6x+10x-8y
to expand brackets, you multiply the number outside by the numbers inside. first -3x3= -9.
-2 by -3 is 6
2 by 5 is 10
2 by -4 is -8

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2 years ago

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A car insurance company suspects that the younger the driver is, the more reckless a driver he/she is. They take a survey and gr

erastovalidia [21]

Answer:

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.

Step-by-step explanation:

We have to construct a confidence interval for the difference of proportions.

The difference in the sample proportions is:

$p_1-p_2=x_1/n_1-x_2/n_2=(183/217)-(322/398)=0.843-0.809\\\\p_1-p_2=0.034$

The estimated standard error is:

$\sigma_{p_1-p_2}=\sqrt{\frac{p_1(1-p_1)}{n_1}+\frac{p_2(1-p_2)}{n_2} } \\\\\sigma_{p_1-p_2}=\sqrt{\frac{0.843*0.157}{217}+\frac{0.809*0.191}{398} } \\\\\sigma_{p_1-p_2}=\sqrt{0.000609912+0.000388239}=\sqrt{0.000998151} \\\\ \sigma_{p_1-p_2}=0.0316$

The z-value for a 95% confidence interval is z=1.96.

Then, the lower and upper bounds are:

$LL=(p_1-p_2)-z*\sigma_p=0.034-1.96*0.0316=0.034-0.062=-0.028\\\\\\UL=(p_1-p_2)+z*\sigma_p=0.034+1.96*0.0316=0.034+0.062=0.096$

The confidence interval for the difference in proportions is

$-0.028\leq p_1-p_2 \leq 0.096$

<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>

No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.

This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.

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2 years ago