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Ymorist [56]
2 years ago
12

Wendy jogs a 5.5-mile route in the city with her running club once a week. She also jogs a nature trail near her home once a wee

k. The nature trail is 1.5 times as long as the route in the city. How many miles does Wendy jog in all each week? Write your answer as a whole number or decimal
Mathematics
1 answer:
insens350 [35]2 years ago
5 0

Answer:

Wendy jogs 13.75 mile in all each week

Step-by-step explanation:

To determine how many miles Wendy jogs in all each week,

we will sum the distance she jogs in the city with her running club in a week to the distance she jogs along the nature trail near her home in a week.

The distance she jugs with her running club = 5.5 mile.

Now, we will determine the distance of the nature trail near her home.

From the question, the nature trail is 1.5 times as long as the route in the city.

Let the distance of the nature trail = x

and the distance of the route in the city be y

Hence, we can write that

x = 1.5 y

distance of the route in the city, y = 5.5 mile

∴ x = 1.5 \times 5.5

x =  8.25 miles

Hence, the nature trail is 8.25 mile

Then, the number of miles Wendy jogs in all each week is

5.5 mile + 8.25 mile = 13.75 mile

Hence, Wendy jogs 13.75 mile in all each week

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Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

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(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

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-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
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30 POINTS A quadrilateral has vertices A(11, -7), B(9, -4), C(11, -1), and D(13, -4). Quadrilateral ABCD is a __________ A.paral
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Answer:

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Step-by-step explanation:

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Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on t
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Answer:

The teacher should use the median for Amo and the mean for Javier.

Complete question;

Mr. Malloy wants to make sure Amo and Javier get the best possible grade after five tests and can either give a grade based on the median or the mean

Test

Number

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Javier’s Scores

1

97

68

2

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97

3

89

65

4

55

92

5

90

65

What measure of center should Mr. Malloy use for Amo and for Javier for the best possible grade?

The teacher should use the mean for both Amo and Javier.

The teacher should use the median for both Amo and Javier.

The teacher should use the median for Amo and the mean for Javier.

The teacher should use the mean for Amo and the median for Javier.

Attached is the image of their scores

Step-by-step explanation:

Amo's Score in Ascending Order: 55,89,90,92,97

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For Amo;

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Median = 90

For Javier;

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Therefore,

Median is higher for Amo and mean is higher for Javier

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b = -8 + 9
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y = 3x + 1
7 0
2 years ago
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