A horticulturist conducted an experiment on 110 thirty-six inch plant boxes to see if the amount of plant food given to the plan
1 answer:
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Answer:
A. 4.26 in^2
Step-by-step explanation:
Step 1: Find the area of the sector DBC. Here we have to use the formula.
Area of a sector = Central Angle/360 *π
The area of the sector DBC = (54/360)*3.14*
= 30.16
Step 2: Area of segment CFD = Area of the sector DBC - Area of the ΔCBD
= 30.17 - 25.9
Area of segment CFD = 4.27in^2
Answer:
The amount of heat required to raise the temperature of liquid water is 9605 kilo joule .
Step-by-step explanation:
Given as :
The mass of liquid water = 50 g
The initial temperature = = 15°c
The final temperature = = 100°c
The latent heat of vaporization of water = 2260.0 J/g
Let The amount of heat required to raise temperature = Q Joule
Now, From method
Heat = mass × latent heat × change in temperature
Or, Q = m × s × ΔT
or, Q = m × s × ( -
)
So, Q = 50 g × 2260.0 J/g × ( 100°c - 15°c )
Or, Q = 50 g × 2260.0 J/g × 85°c
∴ Q = 9,605,000 joule
Or, Q = 9,605 × 10³ joule
Or, Q = 9605 kilo joule
Hence The amount of heat required to raise the temperature of liquid water is 9605 kilo joule . Answer
So,
Mark wants $100 for 10 hrs., or $10/hr.
Rick wants $80 for 9 hrs., or
$8.89/hr.
Steve wants $75 for 8 hrs., or $
/hr. or $9.38/hr.
Finally, Andy wants $60 for 5 hrs., or $12/hr.
We can see that <u>Rick</u> offers the best deal, at $8.89/hr.
Mark wants $100 for 10 hrs., or $10/hr.
Rick wants $80 for 9 hrs., or
Steve wants $75 for 8 hrs., or $
Finally, Andy wants $60 for 5 hrs., or $12/hr.
We can see that <u>Rick</u> offers the best deal, at $8.89/hr.