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2 years ago

Ava said "There are only three hundred 3- diget numbers" is her statement true or faulse

Mathematics

1 answer:

Eduardwww [97]2 years ago

3 0

Answer: False, there are actually 900 different three-digit numbers

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Explanation:

The three digit numbers span from 100 to 999, including both endpoints.

This means we have 999-100+1 = 900 different three-digit numbers.

You subtract the endpoints (large-small) and add 1 to include the lower endpoint.

Here's a smaller example of why this works: say you had the set {1,2,3,4} and we wanted to count the number of items in this set. Clearly there are 4 items. Note how subtracting the endpoints 4-1 gets us 3 instead, so we add on 1 to include that left endpoint.

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Pam served her apple pie on a 13 inch diameter dish. She wanted to tie a ribbon around the dish to make it a little more festive

zlopas [31]

Answer:

Length of ribbon = 40.86 inches

Step-by-step explanation:

Length of the ribbon = circumference of the dish = πD

D = diameter = 13 inches

Length of ribbon = 22/7 x 13 = 40.857143 inches

8 0

2 years ago

Read 2 more answers

Sean pays £10 for 24 chocolate bars. He sells all 24 chocolate bars for 50p each.

VladimirAG [237]

Answer:

the percentage profit is 20%

Step-by-step explanation:

Given that

Sean paid £10 for 24 chocolate bars

He sold all 24 chocolate bars for 50p each

we need to find out the percentage profit

Since he paid £10 and sale value is (24 × 0.50) i.e. £12

So, the percentage profit is

= (£12 - £10) ÷ (£10)

= 20%

Hence, the percentage profit is 20%

4 0

2 years ago

In which set do all of the values make the inequality 2x - 1 < 10 true?

igomit [66]

$2x - 1 < 10\Leftrightarrow 2x < 11\Leftrightarrow x < \frac{11}{2}$

8 0

2 years ago

What is the value of f(x) = –x2 + 3 when x = 1?

Leya [2.2K]

Answer:

f(x) = g(x)

3(2) - 4 = (2)² - 2

6 - 4 = 4 - 2

2 = 2

Step-by-step explanation:

there

5 0

1 year ago

Use Simpson's Rule with n = 10 to estimate the arc length of the curve. Compare your answer with the value of the integral produ

SOVA2 [1]

$y=\ln(6+x^3)\implies y'=\dfrac{3x^2}{6+x^3}$

The arc length of the curve is

$\displaystyle\int_0^5\sqrt{1+\frac{9x^4}{(6+x^3)^2}}\,\mathrm dx$

which has a value of about 5.99086.

Let $f(x)=\sqrt{1+\frac{9x^4}{(6+x^3)^2}}$ . Split up the interval of integration into 10 subintervals,

[0, 1/2], [1/2, 1], [1, 3/2], ..., [9/2, 5]

The left and right endpoints are given respectively by the sequences,

$\ell_i=\dfrac{i-1}2$

$r_i=\dfrac i2$

with $1\le i\le10$ .

These subintervals have midpoints given by

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}4$

Over each subinterval, we approximate $f(x)$ with the quadratic polynomial

$p_i(x)=f(\ell_i)\dfrac{(x-m_i)(x-r_i)}{(\ell_i-m_i)(\ell_i-r_i)}+f(m_i)\dfrac{(x-\ell_i)(x-r_i)}{(m_i-\ell_i)(m_i-r_i)}+f(r_i)\dfrac{(x-\ell_i)(x-m_i)}{(r_i-\ell_i)(r_i-m_i)}$

so that the integral we want to find can be estimated as

$\displaystyle\sum_{i=1}^{10}\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx$

It turns out that

$\displaystyle\int_{\ell_i}^{r_i}p_i(x)\,\mathrm dx=\frac{f(\ell_i)+4f(m_i)+f(r_i)}6$

so that the arc length is approximately

$\displaystyle\sum_{i=1}^{10}\frac{f(\ell_i)+4f(m_i)+f(r_i)}6\approx5.99086$

5 0

2 years ago