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Whitepunk [10]
2 years ago
8

A triangle has a base length of 3.1 cm and corresponding height of 4.2 cm, correct to

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

The upper bound of the area is 6.69375 cm²

The lower bound of the area is 6.32875 cm²

Step-by-step explanation:

The question relates to measurements and accuracy

The given information are;

The base length of the triangle = 3.1 cm

The height of the triangle = 4.2 cm correct to one decimal place

The lower bound for the base length of the triangle = 3.05 cm

The upper bound for the base length of the triangle = 3.15 cm

Similarly, the lower bound for the height of the triangle = 4.15 cm

The upper bound for the height of the triangle = 4.25 cm

The formula for calculating the area of a triangle is given by the following formula;

Area of a triangle = 1/2 × Base × Height

The upper bound of the area = 1/2 × The upper bound of the base × The upper bound of the height

The upper bound of the area = 1/2 × 3.15 × 4.25 = 6.69375 cm²

The upper bound of the area = 6.69375 cm²

The lower bound of the area = 1/2 × The lower bound of the base × The lower bound of the height

∴ The lower bound of the area = 1/2 × 3.05 × 4.15 = 6.32875 cm²

The lower bound of the area = 6.32875 cm²

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. Suppose that at UVA, 76% of all undergraduates are in the College, 10% are in Engineering, 7% are in Commerce, 3% are in Nursi
xxMikexx [17]

Answer: 34.2%

Step-by-step explanation:

76% of undergrads in The College

45% of those are male (since 55% female)

.76 x .45 = 34.2% of all undergrads are males in The College

4 0
2 years ago
The table below shows the ticket rates for whale watching trips offered by Ocean Tours. Age Ticket Price Under three years free
Mamont248 [21]
If there are 40 children aged twelve and under and x of them are under three years old, 40 - x aged three twelve years old. From the 92 people that where taken by the company on whale watching trips, 52 are over twelve years old. The equation that best show the total cost, C is
                                (40 - x)(36) + (52)(48) = C
Rearranging the equation gives,
                                       x = 40 - ((C - 2496)/ 36)
4 0
2 years ago
Printed circuit cards are placed in a functional test after being populated with semiconductor chips. A lot contains 140 cards,
hjlf

Answer:

a) 0.9644 or 96.44%

b) 0.5429 or 54.29%

Step-by-step explanation:

a) The probability that at least 1 defective card is in the sample P(A) = 1 - probability that no defective card is in the sample P(N)

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 20

Total number of non defective cards = 140-20 = 120

P(N) = Number of possible selections of 20 non defective cards ÷ Number of possible selections of 20 cards from all the cards.

P(N) = 120C20/140C20 = 0.0356

From equation 1

P(A) = 1 - 0.0356

P(A) = 0.9644 or 96.44%

b) Using the same method as a) above

P(A) = 1 - P(N) .....1

Given;

Total number of cards = 140

Number selected = 20

Total number of defective cards = 5

Total number of non defective cards = 140-5 = 135

P(N) = 135C20/140C20 = 0.457

From equation 1

P(A) = 1 - 0.4571

P(A) = 0.5429 or 54.29%

8 0
2 years ago
In a West Texas school district the school year began on August 1 and lasted until May 31. On August 1 a Soft Drink company inst
WINSTONCH [101]

Answer:

$95.78

Step-by-step explanation:

f(t) = 300t / (2t² + 8)

t = 0 corresponds to the beginning of August.  t = 1 corresponds to the end of August.  t = 2 corresponds to the end of September.  So on and so forth.  So the second semester is from t = 5 to t = 10.

$T₂ = ∫₅¹⁰ 300t / (2t² + 8) dt

$T₂ = ∫₅¹⁰ 150t / (t² + 4) dt

$T₂ = 75 ∫₅¹⁰ 2t / (t² + 4) dt

$T₂ = 75 ln(t² + 4) |₅¹⁰

$T₂ = 75 ln(104) − 75 ln(29)

$T₂ ≈ 95.78

3 0
2 years ago
Determine whether the dilation from the figure on the left to the figure on the right is an enlargement or a reduction. Then fin
dybincka [34]

Answer:

A.

Step-by-step explanation:

we are going from a large shape to a smaller shape. the proof is that the side lengths go down from 7m to 0.5m. so, it is a reduction.

and the scaling factor s ? what do we need to multiply the original side lengths with to get the new ones ?

7 × s = 0.5 = 1/2

s = (1/2)/7 = (1/2)/(7/1) = (1×1)/(2×7) = 1/14

=> answer A is correct

8 0
2 years ago
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