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Whitepunk [10]
2 years ago
8

A triangle has a base length of 3.1 cm and corresponding height of 4.2 cm, correct to

Mathematics
1 answer:
Svetradugi [14.3K]2 years ago
4 0

Answer:

The upper bound of the area is 6.69375 cm²

The lower bound of the area is 6.32875 cm²

Step-by-step explanation:

The question relates to measurements and accuracy

The given information are;

The base length of the triangle = 3.1 cm

The height of the triangle = 4.2 cm correct to one decimal place

The lower bound for the base length of the triangle = 3.05 cm

The upper bound for the base length of the triangle = 3.15 cm

Similarly, the lower bound for the height of the triangle = 4.15 cm

The upper bound for the height of the triangle = 4.25 cm

The formula for calculating the area of a triangle is given by the following formula;

Area of a triangle = 1/2 × Base × Height

The upper bound of the area = 1/2 × The upper bound of the base × The upper bound of the height

The upper bound of the area = 1/2 × 3.15 × 4.25 = 6.69375 cm²

The upper bound of the area = 6.69375 cm²

The lower bound of the area = 1/2 × The lower bound of the base × The lower bound of the height

∴ The lower bound of the area = 1/2 × 3.05 × 4.15 = 6.32875 cm²

The lower bound of the area = 6.32875 cm²

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Each morning darnell does a combination of aerobics and stretching exercises. the exercises burn different amounts of calories p
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Beck finished 30% of his homework in 12 minutes. How many minutes will it take him to complete all of his homework?
arlik [135]
The correct answer is choice D.  If you put choice D into words, it is saying 30% (0.3) of the total is 12 minutes.

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Points b,d, and f are midpoints of the sides of triangle ACE. EC=30 and DF= 17 find AC
Margaret [11]

Answer:

Your answer should be AC=2DF=34

Step-by-step explanation:


5 0
2 years ago
△ABC has vertices A(−1, 6), B(2, 10), and C(7, −2) . Find the measure of each angle of the triangle. Round decimal answers to th
kolbaska11 [484]

Answer:

<A = 90°, <B = 71.6° <C = 18.4°

Step-by-step explanation:

Given the vertices of a △ABC to be A(−1, 6), B(2, 10), and C(7, −2)

Before we can get each angle of the triangle, we need to get its sides first.

Using the formula fie finding the distance between two points

D = √(x2-x1)²+(y2-y1)²

For side AB:

Given A(−1, 6), B(2, 10)

AB = √{2-(-1)}²+(10-6)²

AB =√3²+4²

AB = √25

AB = 5

For side AC:

Given A(-1,6) and C(7, −2)

AC = √{7-(-1)}²+(-2-6)²

AC = √8²+8²

AC = √128

AC = √64×2

AC = 8√2

For side BC:

Given B(2,10) and C(7, −2)

BC = √(7-2)²+(-2-10)²

BC = √5²+12²

BC = √25+144

BC = √169

BC = 13

First we need to get theta using cosine rule

|AC|² = |AB|+|BC| - 2|AB||AC| cos theta

(8√2)² = 5²+13²-2(5)(13)cos theta

128 = 169-130costheta

128-169 = -130costheta

-41= -130costheta

Costheta = -41/-130

Cos theta = 0.315

theta = arccos 0.315

theta = 71.64°

<B = 71.6°

Using sine rule to get <A,

BC/sin A = AC/sinB

13/sinA = 8√2/sin71.6°

8√2sinA = 13sin71.6°

SinA = 12.34/8√2

SinA = 1.09°

A = arcsin1

<A = 90.0°

<C = 180°-(71.6+90)

< C = 180-161.6

<C = 18.4°

3 0
2 years ago
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