All categories

1 year ago

Lauren spent 3/5 of her money on a refrigerator. The refrigerator cost $756. How much money did she have left?

1 answer:

3 0

Fractions are the part/whole. We can set this up to be...

3/5 = 756
756 x5/3 = 1260.

if she had 1260 to begin with and spent 756, she would have 504.00 left.

You might be interested in

Three percent of Jennie’s skin cells were burned when she escaped from a fire. If 3.7×10’(of her skin cells were burned then, ho

lora16 [44]

Answer:

The quantity of Jennie's skin cell were not burned is 119.601 × $10^{10}$ .

Step-by-step explanation:

Given as :

The percentage of Jennie's skin cell were burned = 3 %

The quantity of Jennie's skin cell were burned = 3.7 × $10^{10}$

Let The quantity of Jennie's skin cell were not burned = x

Let Total quantity of whole skin cell = n

Now, According to question

The quantity of Jennie's skin cell were burned = Total quantity of whole skin cell × percentage of Jennie's skin cell were burned

i.e 3.7 × $10^{10}$ = n × 3 %

Or, 3.7 × $10^{10}$ = n × $\dfrac{3}{100}$

Or, n = 3.7 × $10^{10}$ × $\dfrac{100}{3}$

Or, n = $\frac{3.7\times 10^{12}}{3}$

i.e n = 1.233 × $10^{12}$

Or, Total quantity of whole skin cell = n = 1.233 × $10^{12}$

Now, Again

∵ percentage of Jennie's skin cell were burned = 3 %

So, percentage of Jennie's skin cell were not burned = 100 % - 3 % = 97 %

so , The quantity of Jennie's skin cell were not burned = 97 % of Total quantity of whole skin cell

Or, x = $\frac{97}{100}$ × n

Or, x = $\frac{97}{100}$ × 1.233 × $10^{12}$

∴ x = 119.601 × $10^{10}$

So, The quantity of Jennie's skin cell were not burned = x = 119.601 × $10^{10}$

Hence, The quantity of Jennie's skin cell were not burned is 119.601 × $10^{10}$ . Answer

6 0

2 years ago

On a certain day, the temperature changed at a rate of 3°F per hour. How long did it take for the change in temperature to be -3

mamaluj [8]

Answer:

I think 11 hours.

Step-by-step explanation:

If I know starting temp such as 0 degrees then I can say that it would take 11 hours as 11*3 = 33. If it is 3 degrees, then it would 3*12 = 36 degrees.

7 0

2 years ago

A company manufactures two products X and Y. Each product has to be processed in three departments: welding, assembly and painti

Tems11 [23]

Answer:

100x+120y = z

z= $ 63000

Step-by-step explanation:

Product Welding Assembly Painting Cont. to profit

X 2x hours 3x hours 1xhour = $100x

Y 3y hours 2y hours 1y hour = $120y

Total hours 1500 hours 1500 hours 550 hours

available

Let X represent product X

Let Y represent Product Y

2x + 3y = 1500

x + y = 550

y= 550-x

2x + 3(550-x) = 1500

2x + 1650- 3x = 1500

150 = x

y = 550-150

y = 400

Objective Function Z = 100x + 120y

Z = 100(150) + 120( 400)

Z = 15000+48000

Z = $63000

7 0

2 years ago

Which equation represents the line shown on the graph?

Mama L [17]

Hello there,

To find out the equation you use the slope intercept form...

y = mx + b

M is the slope and b is where the line crosses the y-axis...

Now to find the slope you count the distance from two points so...

The distance from (0,2) to (1,5) is 3 units up and 1 unit over.

So the correct answer should be...

y = 3x + 2

Answer: w = 3z + 2

Hope I helped!!

-Char

8 0

2 years ago

Alice has a 4-inch by 5-inch photo of your school’s championship girls’ ice hockey team. To celebrate their recent

Pachacha [2.7K]

Alice should pick the enlarged-photo with dimensions of 8-inch by 10-inch.

Step-by-step explanation:

Step 1:

In order for a part of the photo to not be cut off, the enlarged photo's dimensions should be of a constant ratio with the original photo's dimensions.

We divide the dimensions of the enlarged-photo with the dimensions of the original photo to check which has a constant ratio.

Step 2:

The original photo was a 4-inch by 5-inch photo.

Option 1 is 7-inch by 9-inch, so the ratios are

$\frac{7}{4} = 1.75, \frac{9}{5} = 1.8.$ The ratios are different so this cannot be the enlarged photo's dimensions.

Option 2 is 8-inch by 10-inch, so the ratios are

$\frac{8}{4} = 2, \frac{10}{5} = 2.$ The ratios are the same so this can be the enlarged photo's dimensions.

Option 3 is 12-inch by 16-inch, so the ratios are

$\frac{12}{4} = 3, \frac{16}{5} = 3.2.$ The ratios are different so this cannot be the enlarged photo's dimensions.

So the enlarged-photo with dimensions of 8-inch by 10-inch should be picked.

7 0

2 years ago