44 tens is the same as

A machine used to fill cereal boxes dispenses, on the average, μ ounces per box. The manufacturer wants the actual ounces dispen

irga5000 [103]

Answer: 1/2

Step-by-step explanation:

First step: we will use Tchebyscheff's theorem. The theorem can help us to explain random variables with finite variance as well as mean.

P (|Y-u| < or equals to 1) | > or equals to 0.75

= 1 - 1/2

Therefore, w= 2

Step 2: we use Tchebyscheff's inequality, which is:

= -2¶ + u < y < 2¶ + u

Therefore, we have; --2¶ + u

= 1 + u

1= K¶

¶ = 1/2.

Please take note that ¶ is represented as sigma symbol.

Since I can't get the symbol here with me. Also the u repres represent 'micro' symbol

4 0

1 year ago

Team A faces loses of 5,876 points in Round 1 . How much is the loss of points for each of the 26 players of Team A if the loss

Svetllana [295]

Answer:

226 points were lost per player

Step-by-step explanation:

Since we are evenly spreading the points between all 26 players, we need to solve using division.

Basically, we are dividing the 5876 points among the 26 players.

5876/26 = 226

Therefore, if the points were spread evenly among all 26 players, each player would lose 226 points.

6 0

2 years ago

A consensus forecast is the average of a large number of individual analysts' forecasts. Suppose the individual forecasts for a

zaharov [31]

Answer:

a) $P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)$

And we can find this probability using the complement rule:

$P(z>-1.25)=1-P(z$

b) $P(X$

And we can find this probability uing the normal standard table:

$P(z$

c) $P(3.5$

And we can find this probability with this difference:

$P(-1.25$

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.

$P(-1.25$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(5,1.2)$