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Vinvika [58]
2 years ago
13

Given the first type of plot indicated in each pair: which of the second plots could not always be generated from it? a. dot plo

t, box plot b. histogram, stem and leaf c. stem and leaf dot plot d. dot plot, histogram
Mathematics
1 answer:
Elenna [48]2 years ago
3 0

Answer:

C

Step-by-step explanation:

Dot plot is usually in the form of stem & leaf. The only difference is that, stem& leaf presents the actual values while dot plot usually represent the value in dots. Hence, we can easily generate dot plot from stem & leaf!

For (a) dot plot and box plot, dot plot presents all the data while box plot presents only the five-num statistics, namely:

1. minimum

2. 1st quartile (Q1)

3. median

4. 3rd quartile (Q3)

5. Maximum

And outliers, if any!

Thus, dot plot cannot directly generate box plot

For (b). Histogram and stem & leaf. Although both usually help us understand the skewness of data distribution, however, histogram deals with frequency distribution (counts of number of occurrence) and plotted on the intervals and stem&leaf list the values.

For (d). Even though dot plot shoots up and down like the histogram, the content is different. In dot plot, it is the actual value represented in dots. But in histogram, it is the frequency distribution of the class intervals.

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At a local baseball game there are 3 hot dog vendors. collectively the vendors sold 1,700 hot dogs. if vendor a sold 456, vendor
Vera_Pavlovna [14]
The answer is C.

Vendor A= 456/1700, which is .268 or 27%
Vendor B= 607/1700, which is .357 or 36%
Vendor C= 637/1700, which is .374 or 37%

For a total of 100%
8 0
2 years ago
Read 2 more answers
If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a
kolbaska11 [484]

Answer:

<h2><em>2(3s-14)</em></h2>

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em></em>

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

8 0
2 years ago
How many intersections are there of the graphs of the equations below? One-halfx + 5y = 6 3x + 30y = 36 none one two infinitely
Sergeu [11.5K]

Answer:

infinitely many

Step-by-step explanation:

You have the system

(1/2)x + 5y = 6

  3x  + 30y = 36

Multiplying the first equation by 6 results in 3x + 30y = 36, which is exactly the same as the second equation.  The two graphs coincide, and so there are infinitely many solutions to this system

4 0
2 years ago
Read 2 more answers
At an ocean-side nuclear power plant, seawater is used as part of the cooling system. This raises the temperature of the water t
grandymaker [24]

Answer:

(a1) The probability that temperature increase will be less than 20°C is 0.667.

(a2) The probability that temperature increase will be between 20°C and 22°C is 0.133.

(b) The probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c) The expected value of the temperature increase is 17.5°C.

Step-by-step explanation:

Let <em>X</em> = temperature increase.

The random variable <em>X</em> follows a continuous Uniform distribution, distributed over the range [10°C, 25°C].

The probability density function of <em>X</em> is:

f(X)=\left \{ {{\frac{1}{25-10}=\frac{1}{15};\ x\in [10, 25]} \atop {0;\ otherwise}} \right.

(a1)

Compute the probability that temperature increase will be less than 20°C as follows:

P(X

Thus, the probability that temperature increase will be less than 20°C is 0.667.

(a2)

Compute the probability that temperature increase will be between 20°C and 22°C as follows:

P(20

Thus, the probability that temperature increase will be between 20°C and 22°C is 0.133.

(b)

Compute the probability that at any point of time the temperature increase is potentially dangerous as follows:

P(X>18)=\int\limits^{25}_{18}{\frac{1}{15}}\, dx\\=\frac{1}{15}\int\limits^{25}_{18}{dx}\,\\=\frac{1}{15}[x]^{25}_{18}=\frac{1}{15}[25-18]=\frac{7}{15}\\=0.467

Thus, the probability that at any point of time the temperature increase is potentially dangerous is 0.467.

(c)

Compute the expected value of the uniform random variable <em>X</em> as follows:

E(X)=\frac{1}{2}[10+25]=\frac{35}{2}=17.5

Thus, the expected value of the temperature increase is 17.5°C.

7 0
2 years ago
An oblique prism has trapezoidal bases and a vertical height of 10 units. An oblique trapezoidal prism is shown. The trapezoid h
denis23 [38]

Answer:

volume of trapezoidal prism = 15x^2 cubic units

Step-by-step explanation:

First, area of the trapezoidal bases.

Parallel sides measure x and 2x, for an average of 1.5x.

Height = x

Area of trapezoidal base = 1.5x*x = 1.5x^2

Volume of prism = area base * height

(length does not matter, height does)

= 1.5x^2 * 10 = 15x^2

5 0
2 years ago
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