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kari74 [83]
1 year ago
5

You are having a pizza-making party. You will need 6 ounces of dough and 4 ounces of sauce for each person at the party (includi

ng yourself, the host). Once you have a total count of guests, you buy exactly the needed amount of all the ingredients. The dough and sauce that you buy weigh 130 ounces all together.
How many ounces of dough did you buy?
How many ounces of sauce did you buy?
How many guests are coming to the party?
Mathematics
1 answer:
Tcecarenko [31]1 year ago
6 0

Answer:

78 ounces of dough

52 ounces of sauce

12 guests are coming (not including you)

Step-by-step explanation:

13x6=78

13x4=52

78+52=130 ounces

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E varies directly with the square root of C. If E=40 when C=25, find: C when E = 10.4
sukhopar [10]

Answer: C = 1.69

Step-by-step explanation:

E is proportional to √C

To remove proportionality, introduce a constant (k).

E = k × √C

From question,

E = 40 and C = 25

So,

40 = k ×√25

40 = k × 5

k = 8

Now,

C = ?

E = 10.4

k = 8

E = k × √C

10.4 = 8 × √C

10.4 / 8 = √C

( 10.4 / 8 ) ^ 2 = C

C = 1.69

6 0
2 years ago
Read 2 more answers
If a person tosses a coin 23 times, how many ways can he get 11 heads
EastWind [94]

Tossing a coin is a binomial experiment.

Now lets say there are 'n' repeated trials to get heads. Each of the trials can result in either a head or a tail.

All of these trials are independent since the result of one trial does not affect the result of the next trial.

Now, for 'n' repeated trials the total number of successes is given by

_{r}^{n}\textrm{C}

where 'r' denotes the number of successful results.

In our case n=23 and r=11,

Substituting the values we get,

_{11}^{23}\textrm{C}=\frac{23!}{11!\times 12!}

\frac{23!}{11!\times 12!}=1352078

Therefore, there are 1352078 ways to get heads if a person tosses a coin 23 times.


3 0
2 years ago
Find the total cost to the nearest cent $43 dinner 18% gratuity
Norma-Jean [14]
43*1.18=$50.74
You pay 100% plus 18% tip
5 0
2 years ago
According to Masterfoods, the company that manufactures M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12% are re
Ipatiy [6.2K]

Answer:

a) 0.88

b) 0.35

c) 0.0144

d) 0.2084

e) 0.7916

Step-by-step explanation:

a) The probability of a peanut being brown is 12/100 = 0.12. Hence the probability of it not being brown is 1-0.12 = 0.88

b) 12% of peanuts are brown, 23% are blue. So 35% are either blue or brown. The probability of a peanut being blue or brown is, therefore 35/100 = 0.35.

c) 12% of peanuts are red, so the probability of a peanut being red is 12/100 = 0.12. In order to calculate the probability of 2 peanuts being both red, we can assume that the proportion doesnt change dramatically after removing one peanut (because the number of peanuts is absurdly high. We can assume that we are replenishing the peanuts). To calculate the probability of 2 peanuts being both red, we need to power 0.12 by 2, hence the probability is 0.12² = 0.0144.

d) Again, we will assume that the probability doesnt change, because we replenish. The probability of a peanut being blue is 0.23. The probability of it not being blue is 0.77, so the probability of 6 peanuts not being blue is obtained from powering 0.77 by 6, hence it is 0.77⁶ = 0.2084

e) The event 'at least one peanut is blue' is te complementary event of 'none peanuts are blue', so the probability of this event is 1- 0.2084 = 0.7916

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2 years ago
Every morning Halle goes to school with a 1 liter bottle of water. She drinks 1/4 of the bottle before school starts and 2/3 of
valkas [14]

Answer:

1 1/3

Step-by-step explanation:

you have to take away 2/3 and 1/4 and add the one and your answer is 1 1/3 and the bottom of the fraction stay the same

3 0
2 years ago
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