All categories

2 years ago

The HCF of the greatest 2- digit number and the greatest 3-digit number is

Mathematics

1 answer:

Natasha_Volkova [10]2 years ago

7 0

Answer:

Step-by-step explanation:

So the greatest 2 digit number is 99 and the greatest 3 digit number is 999

So find the hcf ( highest common factor ) of 99 and 999.

Factors of 99 : 1, 3, 9, 11, 33, 99

Factors of 999 : 1, 3, 9, 27, 37, 111, 333, 999

Common factors : 1, 3, 9

Hcf : 9

HOPE IT HELPED

You might be interested in

A rectangular field has a length of 105 feet and a width of 60 feet. On a map of the field, the width was drawn as 4 inches. Wha

My name is Ann [436]

<span>7 inches represents 105 ft on the map</span>

8 0

2 years ago

Evaluate 1/3 m - 1 - 1/2 n when m = 21 and n = 12

Dmitry_Shevchenko [17]

Answer:

Step-by-step explanation:

1/3(21)-1-1/2(12)

7-1-6=6-6=0

3 0

2 years ago

Body armor provides critical protection for law enforcement personnel, but it does affect balance and mobility. The article "Imp

yKpoI14uk [10]

Answer:

No, there is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that true average task time with armor is less than 2 seconds.

Then, the null and alternative hypothesis are:

$H_0: \mu=2\\\\H_a:\mu< 2$

The significance level is 0.01.

The sample has a size n=52.

The sample mean is M=1.95.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=0.2.

The estimated standard error of the mean is computed using the formula:

$s_M=\dfrac{s}{\sqrt{n}}=\dfrac{0.2}{\sqrt{52}}=0.028$

Then, we can calculate the t-statistic as:

$t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{1.95-2}{0.028}=\dfrac{-0.05}{0.028}=-1.803$

The degrees of freedom for this sample size are:

$df=n-1=52-1=51$

This test is a left-tailed test, with 51 degrees of freedom and t=-1.803, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.039) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that true average task time with armor is less than 2 seconds.

3 0

2 years ago

A frequency distribution is a tabular summary of data showing the a. number of items in several classes. b. relative percentage

Viefleur [7K]

Answer:

The answer is a: Number of items in several classes.

Step-by-step explanation:

Frequency distributions are tables that represent the number of times a specific data, number object etc appears in a sample. So for example if we have this data

2,2,4,4,6,6,6,8,8,10

The frequency distributions is

Number frequency

2 2

4 2

6 3

8 2

10 1

The other options are identical (c and are the same as percentages can be expressed as fractions. Relative percentages or fractions are tables that express the weight that each category has in the entire data. An example for our data would be: (10 are the total number of obs)

Number Fraction/%

2 2/10 or 20%

4 2/10 or 20%

6 3/10 or 30%

8 2/10 or 20%

10 1/10 or 10%

6 0

2 years ago

1/2(6+3p)-3/4(8-10p)<br>Expand and simplify <br>show all steps

olganol [36]

$\frac{6+3p}{2} - \frac{3}{4} (8 - 10p) \\ \\ \frac{6 + 3p}{2} - \frac{3(8-10p)}{4} \\ \\ \frac{6+3p}{2} - \frac{3 \times 2(4 - 5p)}{4} \\ \\ \frac{6+3p}{2} - \frac{6(4-5p)}{4} \\ \\ \frac{6+3p}{2} - \frac{3(4-5p)}{2} \\ \\ \frac{6+3p - 3(4-5p)}{2} \\ \\ \frac{3(2 +p - 4 + 5p}{2} \\ \\ \frac{3(2 + (p + 5p) - 4)}{2} \\ \\ \frac{3(2+6p-4)}{2} \\ \\ \frac{3 \times 2 (1 + 3p-2)}{2} \\ \\ \frac{3 \times 2(3p - 1)}{2} \\ \\ \frac{6(3p -1 }{2} \\ \\ 3(3p - 1) \\ \\ Answer: \fbox {3(3p-1)}$

7 0

2 years ago