Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
Answer: The difference of 6 times a number m and 2
Step-by-step explanation:
The way to write this expression is:
The difference of 6 times a number m and 2.
Answer:
Option C is the correct option.
Step-by-step explanation:
Considering the triangle ABC, the slope of the line CA is given by 
Again, considering the triangle CDE, the slope of the line EC is given by
Since CA and EC represents the same straight line so, we can write
Therefore, option C is the correct option. (Answer)
So to get the answer you multiply 48 by 1.15 and you get 55.2
Chung's go-kart can travel 55.2 miles on 1.15 gallons of gas.
(24, 12) and (36, 0). The least amount of flowering plants occurs when x=2y, and the largest amount occurs when y=0. These two points satisfy both conditions and both sum to 36.
