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goldfiish [28.3K]
2 years ago
9

Triangle ABC and triangle CDE are similar right triangles. Which proportion can be used to show that the slope of AC is equal to

the slope of CE?
A) 6 − 3
−3 − 1
= 3 − (−3)
−1 − 3

B) 6 − 3
−3 − (−1)
= 3 − 3
−1 − 3

C) 6 − 3
−3 − (−1)
= 3 − (−3)
−1 − 3

D) −3 − (−1)
6 − 3
= 3 − (−3)
−1 − 3

Mathematics
1 answer:
shusha [124]2 years ago
8 0

Answer:

Option C is the correct option.

Step-by-step explanation:

Considering the triangle ABC, the slope of the line CA is given by \frac{AB}{BC} = \frac{6 - 3}{-3 - (- 1)}

Again, considering the triangle CDE, the slope of the line EC is given by

\frac{CD}{DE} = \frac{3 - (- 3)}{- 1 - 3 }

Since CA and EC represents the same straight line so, we can write

\frac{6 - 3}{-3 - (- 1)} = \frac{3 - (- 3)}{- 1 - 3 }

Therefore, option C is the correct option. (Answer)

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To find the area of parallelogram RSTU, Juan starts by drawing a rectangle around it. Each vertex of parallelogram RSTU is on a
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C. (18+4)

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Which ordered pairs are solutions to the inequality 2y−x≤−6 ?
Vinil7 [7]
Given inequality: 2y−x ≤ −6

Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied

Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
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Option-3 : (1, -4)
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Option-4 : (0, -3)
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Option-5 : (2, -2)
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Solutions are: (1, -4), (0, -3) , (2, -2)

4 0
2 years ago
A manufacturer of paper coffee cups would like to estimate the proportion of cups that are defective (tears, broken seems, etc.)
Maksim231197 [3]

Answer:

a

  The 95% confidence interval is  0.0503  <   p < 0.1297

b

The sample proportion is  \r p =  0.09

c

The critical value is  Z_{\frac{\alpha }{2} } =  1.96

d

 The standard error is  SE   =0.020

Step-by-step explanation:

From the question we are told that

   The  sample size is  n =  200

     The number of defective is  k =  18

The null hypothesis is  H_o  :  p  =  0.08

The  alternative hypothesis is  H_a  :  p > 0.08

Generally the sample proportion is mathematically evaluated as

            \r p =  \frac{18}{200}

            \r p =  0.09

Given that the confidence level is  95% then the level  of significance is mathematically evaluated as

        \alpha  =  100 -  95

        \alpha  =  5\%

        \alpha  =  0.05

Next we obtain the critical value of  \frac{ \alpha }{2} from the normal distribution table, the value is  

        Z_{\frac{\alpha }{2} } =  1.96

Generally the standard of error is mathematically represented as

          SE   =  \sqrt{\frac{\r p (1 -  \r p)}{n} }

substituting values

         SE   =  \sqrt{\frac{0.09  (1 -  0.09)}{200} }

        SE   =0.020

The  margin of error is  

       E =  Z_{\frac{ \alpha }{2} }  * SE

=>    E =  1.96  *  0.020

=>   E =  0.0397

The  95% confidence interval is mathematically represented as

     \r p  -  E  <  \mu <  p <  \r p  + E

=>   0.09 - 0.0397  <  \mu <  p < 0.09 + 0.0397

=>  0.0503  <   p < 0.1297

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Answer:

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