Scenarios B, D, and F require a police officer. In scenario B, 1:00-2:00pm, and scenario F, 5:00-6:00pm, there are 24 cars. In scenario D, 3:00-4:00pm, there are 21 cars. Both 24 and 21 are greater than 17, so a traffic officer is needed. However, in other scenarios, the number of cars are all less than 17, and no officer is needed.
Answer:
The standard deviation of car age is 2.17 years.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 7.5
(a) If 99.7% of the ages are between 1 year and 14 years, what is the standard deviation of car age?
This means that 1 is 3 standard deviations below the mean and 14 is 3 standard deviations above the mean.
So
I want to find 
The standard deviation of car age is 2.17 years.
I think that Devon swam at least 35 minutes each day for 5 days because if he exercised 225 minutes and each day he walked for 10 minutes then if you divide 225 by 5 you get 45 so every day he exercised 45 minutes and since he walked for 10 minutes you subtract 10 from 45 which gives you 35 so he swam for 35 minutes.
Answer:
The total cost of the lunch including the tip is $15.21.
Step-by-step explanation:
To find the total cost of the lunch including the tip, first, you need to calculate 17% of the price of the lunch as the statement indicates that that is the tip Joseph leaves the waiter:
$13*17%=$2.21
Now, you need to add that amount to the price of the lunch:
$13+$2.21=$15.21
According to this, the answer is that the total cost of the lunch including the tip is $15.21.
