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irina1246 [14]
2 years ago
5

To make a profit, a clothing store sells jeans at 115% the amount they paid for them. How much did the store pay for the jeans s

hown?
Mathematics
1 answer:
Svetllana [295]2 years ago
8 0

Answer:

The store paid 6.67 times the profit made on the jeans

Step-by-step explanation:

Let the amount the clothing store pay for Jean be X

Let the amount the clothing store sells Jean be Y = X ×1.15

The profit (P) made is the difference between amount the clothing store sells Jean and the amount paid for Jean = Y - X = 1.15X - X

Profit (P)  = 0.15X

X =  P/0.15 = 6.67P

Therefore, the store paid 6.67 times the profit made on the jeans

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To solve for the length of the frame, we are actually solving for the circumference of the circle. Circumference is the measure of the length around edge of the circle. It is given by the formula C=2πr, where r is the radius.

D = 20 in
r = D/2 = 20 in/2 = 10 in
C = 2π(10 in) = 20π in ≈ 62.83 in

The metal frame is about 62.83 inches long. 
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Determine b , given that A = 63°, C = 49°, and c = 3. Round answers to the nearest whole number. Do not use a decimal point or e
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Angle B = 68 degrees
Using the Law of Sines
b / sin(B) = c / sin (C)
b = sin (68) * c / sin (49)
b = 0.92718 * 3 / 0.75471
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<span> <span> <span> b = 3.6855745916


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Using cell references, enter a formula in cell B6 to calculate monthly payments for the loan described in this worksheet. The an
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Answer:

Follows are the solution to this question:

Step-by-step explanation:

Following are the step which is used in the question:

  • Step 1, In this use the sheet on the formulas tab we use the function, that is the part of the FLG "Function Library group".
  • Step 2, In this step, click the Financial button, and after that click on the PMT.  
  • Step 3, after clicking on PMT apply or Enter the value that is "B3/12", in this it provides the rate argument box.
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Unit 7 polygons &amp; quadrilaterals homework 3: rectangles Gina Wilson answer key
Irina-Kira [14]

Answer:

In the image attached you can find the Unit 7 homework.

We need to findt he missing measures of each figure.

<h3>1.</h3>

Notice that the first figure is a rectangle, which means opposite sides are congruent so,

VY = 19

WX = 19

YX = 31

VW = 31

To find the diagonals we need to use Pythagorean's Theorem, where the diagonals are hypothenuses.

VX^{2}=19^{2}+31^{2}\\ VX=\sqrt{361+961}=\sqrt{1322}  \\VX \approx 36.36

Also, YW \approx 36.36, beacuse rectangles have congruent diagonals, which intercect equally.

That means, ZX = \frac{VX}{2} \approx \frac{36.36}{2}\approx 18.18

<h3>2.</h3>

Figure number two is also a rectangle.

If GH = 14, that means diagonal GE = 28, because diagonals intersect in equal parts.

Now, GF = 11, because rectangles have opposite sides congruent.

DF = 28, because in a reactangle, diagonals are congruent.

HF = 14, because its half of a diagonal.

To find side DG, we need to use Pythagorean's Theorem, where GE is hypothenuse

GE ^{2}=11^{2}+DG^{2}\\28^{2}-11^{2}=DG^{2}\\DG=\sqrt{784-121}=\sqrt{663}\\  DG \approx 25.75

<h3>3.</h3>

This figure is also a rectangle, which means all four interior angles are right, that is, equal to 90°, which means angle 11 and the 59° angle are complementary, so

\angle 11 +59\°=90\°\\\angle 11=90\°-59\°\\\angle 11=31\°

Now, angles 11 and 4 are alternate interior angles which are congruent, because a rectangle has opposite congruent and parallel sides.

\angle 4  = 31\°

Which means \angle 3 = 59\°, beacuse it's the complement for angle 4.

Now, \angle 6 = 59\°, because it's a base angle of a isosceles triangle. Remember that in a rectangle, diagonals are congruent, and they intersect equally, which creates isosceles triangles.

\angle 9=180-59-59=62, by interior angles theorem.

\angle 8 =62, by vertical angles theorem.

\angle 10 = 180- \angle 9=180-62=118\°, by supplementary angles.

\angle 7 = 118\°, by vertical angles theorem.

\angle 5=90-59=31, by complementary angles.

\angle 2 = \angle 5 = 31\°, by alternate interior angles.

\angle 1 = 59\°, by complementary angles.

<h3>4.</h3>

m\angle BCD=90\°, because it's one of the four interior angles of a rectangle, which by deifnition are equal to 90°.

m\angle ABD = 6\° = m\angle BDC, by alternate interior angles and by given.m\angle CBE=90-6=84, by complementary angles.

m\angle ADE=90-6=84, by complementary angles.

m\angle AEB=180-6-6=168\°, by interior angles theorem.

m\angle DEA=180-168=12, by supplementary angles.

<h3>5.</h3>

m\angle JMK=180-126=54, by supplementary angles.

m\angle JKH=\frac{180-54}{2}=\frac{126}{2}=63, by interior angles theorem, and by isosceles triangle theorem.

m\angle HLK=90\°, by definition of rectangle.

m\angle HJL=\frac{180-126}{2}=27, by interior angles theorem, and by isosceles triangle theorem.

m\angle LHK=90-27=63, by complementary angles.

m\angle = JLK= m\angle HJL=27, by alternate interior angles.

<h3>6.</h3>

The figure is a rectangle, which means its opposite sides are equal, so

WZ=XY\\7x-6=3x+14\\7x-3x=14+6\\4x=20\\x=\frac{20}{4}\\ x=5

Then, we replace this value in the expression of side WZ

WZ=7x-6=7(5)-6=35-6=29

Therefore, side WZ is 29 units long.

<h3>7.</h3>

We know that the diagonals of a rectangle are congruent, so

SQ=PR\\11x-26=5x+28\\11x-5x=28+26\\6x=54\\x=\frac{54}{6}\\ x=9

Then,

PR=5x+28=5(9)+28=45+28=73

Therefore, side PR is 73 units long.

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This is a linear graph where the y-int. Is (0,-4) and the x-int. Is (2,0)

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