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2 years ago

9

Calculating Profit Using this table, calculate the profit at each level of bicycle production. One bike: -$ Two bikes: $ Three b

ikes: $ Four bikes: $ Five bikes: $ Six bikes: $ Seven bikes: $

1 answer:

leonid [27]2 years ago

8 0

Answer:

1~30

2~3

3~40

4~70

5~90

6~90

7~80

Step-by-step explanation:

subtract the total revenue from the total cost

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A researcher is studying psychological factors in academic achievement among teenage girls. One variable she is particularly int

horrorfan [7]

Answer:

The correct answer is:option A and B

Step-by-step explanation:

A researcher is studying and examining psychological factors in academic achievement amongst teenage boys. One of the variable he is particularly paying more attention is in determination.

The quantifying of variability for the variable determination suggests how stretched out are the values for determination amid teenage boys (do all boys that are still in their teenage years have the same determination) and how constant are the values of determination amid teenage boys.

6 0

2 years ago

John Johnson is forty-seven. He is purchasing twenty-year endowment insurance, with a face value of $20,000. What is his annual

Alenkinab [10]

The answer is Letter D - 939.80.

You can refer to the attachment for the rate. Since he is forty-seven years old, use that age to find his rate under a twenty-year endowment insurance. In this case, the rate is 46.99. Multiply that rate to 20 since he purchased a 20-year endowment insurance with a face value of $20,000. (20,000/1,000 = 20)

46.99 x 20 = 939.80

4 0

2 years ago

Solve 4/x-4=x/x-4-4/3 for x and determine if the solution is extraneous or not

4vir4ik [10]

<u>Answer:</u>

x = 4 (extraneous solution)

<u>Step-by-step explanation:</u>

$\frac { 4 } { x - 4 } = \frac { x } { x - 4 } - \frac { 4 } { 3 } \\ \frac { 4 } { x - 4 } - \frac { x } { x - 4 } = - \frac { 4 } { 3 } \\ \frac { 4 - x } { x - 4 } = - \frac { 4 } { 3 } \\ 3 ( 4 - x ) = - 4 ( x - 4 ) \\ 1 2 - 3 x = - 4 x + 1 6 \\ 4 x - 3 x = 1 6 - 1 2 \\ x = 4 \\$

This solution is extraneous. Reason being that even if it can be solved algebraically, it is still not a valid solution because if we substitute back $x=4$ , we will get two fractions with zero denominator which would be undefined.

7 0

2 years ago

Kenny types 280 words. How long did he <br> type for?<br> A.4<br> B. 5<br> C.6<br> D. 7

zlopas [31]

Are you sure you didn’t miss anything while writing the question?

Cause we have nothing to go off. Everybody types differently so there is no way for us to say how long he typed for, unless we were given aprox how many words he wrote in a minute or something

5 0

2 years ago

Read 2 more answers

An investor believes that investing in domestic and international stocks will give a difference in the mean rate of return. They

arlik [135]

Answer:

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X_1 =2.0233$ represent the sample mean 1

$\bar X_2 =3.048$ represent the sample mean 2

n1=15 represent the sample 1 size

n2=15 represent the sample 2 size

$s_1 =4.893387$ population sample deviation for sample 1

$s_2 =5.12399$ population sample deviation for sample 2

$\mu_1 -\mu_2$ parameter of interest at 0.1 of significance so the confidence would be 0.9 or 90%

We want to test:

H0: $\mu_1 = \mu_2$

H1: $\mu_1 \neq \mu_2$

And we can do this using the confidence interval for the difference of means.

Solution to the problem

The confidence interval for the difference of means is given by the following formula:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}$ (1)

The point of estimate for $\mu_1 -\mu_2$ is just given by:

$\bar X_1 -\bar X_2 =2.0233-3.048=-1.0247$

The degrees of freedom are given by:

$df = n_1 +n_2 -2 = 15+15-2=28$

Since the Confidence is 0.90 or 90%, the value of $\alpha=0.1$ and $\alpha/2 =0.05$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.05,28)".And we see that $t_{\alpha/2}=\pm 1.701$

Now we have everything in order to replace into formula (1):

$-1.0247-1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=-4.137$

$-1.0247+1.701\sqrt{\frac{4.893387^2}{15}+\frac{5.12399^2}{15}}=2.087$

So on this case the 90% confidence interval would be given by $-4.137 \leq \mu_1 -\mu_2 \leq 2.087$

For this case since the confidence interval for the difference of means contains the 0 we can conclude that we don't have significant differences at 10% of significance between the two means analyzed.

4 0

2 years ago