Answer: This is what Khan Academy said the answer was
Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola
that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy. Which is the first error that Tomas made? Tomas substituted the 3 for x when he should have substituted 6 for x. Tomas added 6 to both sides of the equation instead of subtracting 6. Tomas should have written the equation as . Tomas substituted 3 for x when he should have substituted 3 for y.(for edgenuit/y)
2 answers:
Answer:
Tomas added 6 to both sides of the equation instead of subtracting 6.
Step-by-step explanation:
Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation 2x + 6y = 12 to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy.
Given:
2x + 6y = 12
where
x = number of pounds of granola y = number of pounds of walnuts
The correct solution to the problem
x = 3 pounds
2x + 6y = 12
2(3) + 6y = 12
6 + 6y = 12
Subtract 6 from both sides
6 + 6y - 6 = 12 - 6
6y = 6
Divide both sides by 6
y = 6/6
= 1
y = 1 pound
Tomas added 6 to both sides of the equation instead of subtracting 6.
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Step-by-step explanation:
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Answer:
a: 28 < µ < 34
Step-by-step explanation:
We need the mean, var, and standard deviation for the data set. See first attached photo for calculations for these...
We get a mean of 222/7 = 31.7143
and a sample standard deviation of: 4.3079
We can now construct our confidence interval. See the second attached photo for the construction steps.
They want a 90% confidence interval. Our sample size is 7, so since n < 30, we will use a t-score. Look up the value under the 10% area in 2 tails column, and degree of freedom is 6 (degree of freedom is always 1 less than sample size for confidence intervals when n < 30)
The t-value is: 1.943
We rounded down to the nearest person in the interval because we don't want to over estimate. It said 28.55, so more than 28 but not quite 29, so if we use 29 as the lower limit, we could over estimate. It's better to use 28 and underestimate a little when considering customer flow.
