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Tpy6a [65]
2 years ago
9

Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola

that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy. Which is the first error that Tomas made? Tomas substituted the 3 for x when he should have substituted 6 for x. Tomas added 6 to both sides of the equation instead of subtracting 6. Tomas should have written the equation as . Tomas substituted 3 for x when he should have substituted 3 for y.(for edgenuit/y)

Mathematics
2 answers:
expeople1 [14]2 years ago
5 0

Answer:

Tomas added 6 to both sides of the equation instead of subtracting 6.

Artist 52 [7]2 years ago
3 0

Answer:

Tomas added 6 to both sides of the equation instead of subtracting 6.

Step-by-step explanation:

Tomas is making trail mix using granola and walnuts. He can spend a total of $12 on the ingredients. He buys 3 pounds of granola that costs $2.00 per pound. The walnuts cost $6 per pound. He uses the equation 2x + 6y = 12 to represent the total cost, where x represents the number of pounds of granola and y represents the number of pounds of walnuts. He solves the equation for y, the number of pounds of walnuts he can buy.

Given:

2x + 6y = 12

where

x = number of pounds of granola y = number of pounds of walnuts

The correct solution to the problem

x = 3 pounds

2x + 6y = 12

2(3) + 6y = 12

6 + 6y = 12

Subtract 6 from both sides

6 + 6y - 6 = 12 - 6

6y = 6

Divide both sides by 6

y = 6/6

= 1

y = 1 pound

Tomas added 6 to both sides of the equation instead of subtracting 6.

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The answer is 2.95 × 10²³ atoms

Atomic mass is 200.59 g.
So, 1 mole has 200.59 g. Let's calculate how many moles have 98.3 g:
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To calculate this, we will use Avogadro's number which is the number of units (atoms, molecules) in 1 mole of substance:

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