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2 years ago

Chelsea has 11 times as many art brushes as Monique. If they have 60 art brushes altogether, how many brushes does Chelsea have?

1 answer:

7 0

Let Monique's number of art brushes be m.
Then, since Chelsea has <span>11 times as many art brushes as Monique, Chelsea has 11m brushes.

Together they have 60 art brushes, so we write the equation:

m+11m=60.

This means that 12m=60, dividing both sides of the equation by 12 we get m=5.

Chelsea has 11m=11*5=55 brushes.

Answer: 55</span>

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The table below shows a baseball player’s batting average batting left and right versus left- and right-handed pitches Left-hand

Assoli18 [71]

Answer:

C. 11 is the correct answer

Step-by-step explanation:

The table representing the probabilities of player's batting average is,

Left-Handed pitchers Right-Handed pitchers

Bats Left 0.285 0.175

Bats Right 0.215 0.250

So, when the players bats left 100 times,

The probability of hits he gets when faced by left-handed pitchers = 0.285 × 100 = 28.5

The probability of hits he gets when faced by right-handed pitchers = 0.175 × 100 = 17.5

Thus, the difference in the hits = 28.5 - 17.5 = 11

Hence, the player will get 11 more hits t when he faces left-handed pitchers as opposed to right-handed pitchers.

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1 year ago

A girl had 20 coins in nickels and dimes whose sum was $1.40. She spent 65cents , using 8 coins. She now has ? nickels.

abruzzese [7]

Answer:

$0.75 nickels

Step-by-step explanation:

$1.40-$0.65=$0.75

$0.75 nickels

6 0

2 years ago

Read 2 more answers

Implicit information requires the reader to combine details from the text with background knowledge to make a(n) . -guess -theor

klio [65]

The correct answer that would best complete the given statement above would be the third option: INFERENCE. <span>Implicit information requires the reader to combine details from the text with background knowledge to make an inference. An inference is a conclusion that is based on evidence or reasoning. </span>

3 0

2 years ago

Read 2 more answers

A 700 g dry fruit pack costs ₹216 .It contains some almonds and the rest cashew kernel.If almonds cost ₹288 per kg and cashew ke

slamgirl [31]

Answer:

Almonds = 400grams

Cashew = 300 grams

Step-by-step explanation:

Let the grams of cashew be represented by = C

the grams of almonds be represented by = A

A 700 g dry fruit pack costs ₹216 .It contains some almonds and the rest cashew kernel

C + A = 700g ......Equation 1

C = 700 - A

If almonds cost ₹288 per kg and cashew kernel cost ₹336 per kg

Let's convert them to grams

1 kg = 1000grams

For almonds

= 288/1000 = 0.288g

For cashew

= 336/1000 = 0.336g

Hence,

0.288 × A + 0.336g × C = ₹216

0.288A + 0.336C = 216

From Equation 1, substitute 700 - A for C in Equation 2

0.288A + 0.336(700 - A) = 216

0.288A + 235.2 - 0.336A = 216

Collect like terms

0.288A - 0.336A = 216 - 235.2

- 0.048A = -19.2

A = -19.2/-0.048

A = 400 grams

Substitute 400g for a in Equation 1

C + A = 700g ......Equation 1

= C + 400g = 700g

C = 700g - 400g

C = 300g

Therefore, the number of grams of Almonds = 400grams

Cashew = 300 grams

6 0

2 years ago

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

2 years ago