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EastWind [94]
2 years ago
10

A parallelogram has a base of 10 centimeters and a height of 4 centimeters. What is the area of the parallelogram?

Mathematics
1 answer:
Illusion [34]2 years ago
5 0

Step-by-step explanation:

Area of a parallelogram=base×height

=10×4

=40cm^2

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How many inches are equivalent to 2 meters? Round your answer to the nearest tenth em Units The measurement 2 meters is equivale
hjlf

Answer:

78.7

Step-by-step explanation:

2 m = 78.7402

Rounded to nearest tenth-

78.7

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Write value of each digit in 167.7
Usimov [2.4K]

Answer:

no

Step-by-step explanation:

im just getting points

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2 years ago
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Given: The coordinates of triangle PQR are P(0, 0), Q(2a, 0), and R(2b, 2c).
masha68 [24]

Answer:

The line containing the midpoints of two sides of a triangle is parallel to the third side ⇒ proved down

Step-by-step explanation:

* Lets revise the rules of the midpoint and the slope to prove the

  problem

- The slope of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid-point of a line whose endpoints are (x1 , y1) and (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

* Lets solve the problem

- PQR is a triangle of vertices P (0 , 0) , Q (2a , 0) , R (2b , 2c)

- Lets find the mid-poits of PQ called A

∵ Point P is (x1 , y1) and point Q is (x2 , y2)

∴ x1 = 0 , x2 = 2a and y1 = 0 , y2 = 0

∵ A is the mid-point of PQ

∴ A=(\frac{0+2a}{2},\frac{0+0}{2})=(\frac{2a}{2},\frac{0}{2})=(a,0)

- Lets find the mid-poits of PR which called B

∵ Point P is (x1 , y1) and point R is (x2 , y2)

∴ x1 = 0 , x2 = 2b and y1 = 0 , y2 = 2c

∵ B is the mid-point of PR

∴ B=(\frac{0+2b}{2},\frac{0+2c}{2})=(\frac{2b}{2},\frac{2c}{2})=(b,c)

- The parallel line have equal slopes, so lets find the slopes of AB and

  QR to prove that they have same slopes then they are parallel

# Slope of AB

∵ Point A is (x1 , y1) and point B is (x2 , y2)

∵ Point A = (a , 0) and point B = (b , c)

∴ x1 = a , x2 = b and y1 = 0 and y2 = c

∴ The slope of AB is m=\frac{c-0}{b-a}=\frac{c}{b-a}

# Slope of QR

∵ Point Q is (x1 , y1) and point R is (x2 , y2)

∵ Point Q = (2a , 0) and point R = (2b , 2c)

∴ x1 = 2a , x2 = 2b and y1 = 0 and y2 = 2c

∴ The slope of AB is m=\frac{2c-0}{2b-2a}=\frac{2c}{2(b-c)}=\frac{c}{b-a}

∵ The slopes of AB and QR are equal

∴ AB // QR

∵ AB is the line containing the midpoints of PQ and PR of Δ PQR

∵ QR is the third side of the triangle

∴ The line containing the midpoints of two sides of a triangle is parallel

  to the third side

6 0
2 years ago
The function f(x) = –10(x)(x – 4) represents the approximate height of a projectile launched from the ground into the air with a
sineoko [7]
The height of the project becomes zero when it hits the ground which is also the total time at which the projectile stays in the air. Equating the function to zero:
-10(x)(x - 4) = 0
The roots of this quadratic equation are:
x = 0, and x=4

Therefore, the projectile stays in the air for
4 seconds

4 0
2 years ago
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Coach Wilson ordered T-shirts for the basketball team from two different T-shirt suppliers. One supplier charged $16 for each sh
zhuklara [117]
Part A:
# of shirts bought in total (T)times cost of each shirt (E) =X. X times .5 (same as 5%)= shipping charge (S) =
first: T*E=X. second: X*.5=S

Part B:
vendor 1:
# of shirts bought (A) times cost of each shirt (B) plus shipping charge(C) times 10%=T. A*B+C*.10=T

vendor 2:
# of shirts bought (A) times cost of each shirt (B) plus shipping charge (C) minus $20= T. A*B+C-20=T

Part C:

vendor 1:
15*16=240 (total # of shirts * cost of ea.)
240+8= 248 (1st answer + $8 of shipping)
248*.10= 24.80 (2nd answer * 10% discount)
248-24.80= [223.20] (2nd answer - 10%)
vendor 1 total cost: 223.20.


vendor 2:
15*18=270 (# of shirt bought * cost of ea.)
270+12.60=280.60 (answr 1 + shipping cost)
280.60-20=[260.60](answr 2 -$20discount)
vendor 2 total cost: 260.60.
4 0
2 years ago
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