10500-4500=6000
6000/250=24
So the answer is 24 months, or 2 years.
Answer:
$28.50
Step-by-step explanation:
21 chicken wings= $39.90
1 chicken wing= 39.90÷21= $1.90
15 chicken wings= 15×1.90= $28.50
Answer :E) Not enough information is given to determine the probability.
Step-by-step explanation:
Le A denotes the event that households in the United States own dogs .
and B denotes the event that households in the United States own cats.
As per given , we have
P(A)=36.5%= 0.365
P(B)=30.4% = 0.304
To find the probability that the selected household will own a dog or a cat, we apply the following formula :
P(A or B)=P(A)+P(B)+P(A and B)
But P(A and B) is not given to us.
i..e the probability that a house hold own both a cat and adg is not given to us.
Therefore, The correct option is (E) Not enough information is given to determine the probability.
Answer:
50 miles.
Step-by-step explanation:
Edmund fills his gas tank on Monday morning an then drives ten miles total for work each day of the work week.
With a full tank of gas he can drive 100 miles.
Question asked:
How many miles can he drive on the weekend, before he he fills up again?
Solution:
With full tank he can drive a total distance = 100 miles
Each day of the work week, he drives = 10 miles
Total miles, he drive in whole work week (Monday - Friday) = 
<em>Now, to find that many miles he can drive on the weekend (Saturday and Sunday), we will subtract total miles, he drive in whole work week from the total distance, he can drive with full tank of gas:-</em>
100 - 50 = 50 miles.
Therefore, he can drive 50 miles on the weekend, before he he fills up again.
Let stadium 1 be the one on the left and stadium 2 the one on the right.
Angle above stadium 1 is 72.9° and the angle above stadium 2 is 34.1° using the angle property of alternate angles(because both the ground and the dotted line are parallel).
For the next part we need to use the trigonometric function of tangent.
As tan x = opposite / adjacent,
Tan 72.9°=1500/ adjacent ( the ground from O to stadium 1)
Therefore the adjacent is 1500/tan 72.9°= 461.46 m( to 5 s.f.)
Same for the next angle,
Tan 34.1°=1500/ adjacent ( the ground from O to stadium 2)
Therefore, the adjacent is 1500/tan 34.1° = 2215.49 m (to 5 s.f.)
Thus, the distance between both stadiums is 2215.49-461.46= 1754.03 m
Correcting the answer to whole number gives you 1754 m which is the option C.