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1 year ago

Increase £16470.45 by 3.5% answer rounded to 2 DP.

Mathematics

1 answer:

soldier1979 [14.2K]1 year ago

7 0

$\displaystyle\bf 16470,45\cdot(1+0,035)=17046,\underline{91}5\approx17046,92$

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According to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market. A random sample of 70 users

Natalija [7]

Answer:

Probability that 32 or more from this sample used Internet Explorer as their browser is 0.9015.

Step-by-step explanation:

We are given that according to Net Market Share, Microsoft's Internet Explorer browser has 53.4% of the global market.

A random sample of 70 users was selected.

Let $\hat p$ = sample proportion of users who used Internet Explorer as their browser.

The z score probability distribution for sample proportion is given by;

Z = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, p = population proportion of users who use internet explorer = 53.4%

$\hat p$ = sample proportion = $\frac{32}{70}$ = 0.457

n = sample of users = 70

Now, probability that 32 or more from this sample used Internet Explorer as their browser is given by = P( $\hat p$ $\geq$ 0.457)

P( $\hat p$ $\geq$ 0.457) = P( $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ $\geq$ $\frac{0.457-0.534}{\sqrt{\frac{0.457(1-0.457)}{70} } }$ ) = P(Z $\geq$ -1.29)

= P(Z $\leq$ 1.29) = 0.9015

The above probability is calculated by looking at the value of x = 1.29 in the z table which has an area of 0.9015.

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2 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 449 gram setting. It is

stealth61 [152]

Answer:

We accetp H₀

Step-by-step explanation:

Information:

Normal distribution

Population mean = μ₀ = 449

Population standard deviation σ unknown

Sample size n = 23 n < 30 we use t-student test

so n = 23 degree of fredom df = n - 1 df = 23- 1 df = 22

Sample mean μ = 448

Sample standard deviation s = 20

Significance level α = 0,05

1.-Hypothesis Test

Null hypothesis H₀ μ₀ = 449

Alternative hypothesis Hₐ μ₀ ≠ 449

Problem statement ask for determine decision rule for rejecting the null hypothesis. For rejecting the null hypothesis we have to get an statistic parameter wich implies that μ is bigger or smaller than μ₀

2.-Significance level α = 0,05 ; as we have a two tail test

α/2 = 0,025

Then from t - student table for df = 22 and 0,025 (two tail-test)

t(c) = ± 2.074

3.- Compute t(s)

t(s) = ( μ - μ₀ ) / s /√n

plugging in values

t(s) = (448 - 449) / 20 /√23 ⇒ t(s) = - 1*√23 /20

t(s) = - 0.2398

4.-Compare t(c) and t(s)

t(s) < t(c) - 0.2398 < - 2.074

Therefore t(s) in inside acceptance region. We accept H₀

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2 years ago

A warehouse has boxes that are 18 inches tall and other boxes that are 30 inches tall. If 18 inch boxes is stacked next to 30 in

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90 inches 18 times 5 is 90 and 30 times 3 is 90 so the lowest point which they will be at the height is 90 inches

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BlackZzzverrR [31]

Hello,

a) | |PA|-π |>| |PB|-π | (see pic)

c) 3.14< x/113 <=π <22/7

==>3.14*113<x<22/7 * 113
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==>x=355

Answer 355/113=3,1415929203539823008849557522124

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2 years ago

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2 years ago

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