We know, 1 g = 1000 mg
so, 1 mg = 1/1000 g
then, 8,450 mg = 1/1000 * 8,450 = 8.450 g
In short, Your Answer would be: 8.450 Grams
Hope this helps!
Time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours
<h3><u>Solution:</u></h3>
Given it takes Max 1.8 hours to walk home from work at a rate of 3.5km/h
We have to find time taken by Max to cover the same distance walking at 4.2 km/h
<em><u>The relation between speed and time is given as:</u></em>
<em><u>CASE 1:</u></em>
It takes Max 1.8 hours to walk home from work at a rate of 3.5km/h
Let us first find the distance covered
Time taken = 1.8 hours and speed = 3.5 km/hr
Hence distance covered is 6.3 km
<em><u>Now we have to find the time taken to cover same 6.3 km walking at 4.2 km\hr</u></em>
So time taken by Max to cover the same distance walking at 4.2 km/h is 1.5 hours
Answer:
Step-by-step explanation:
D)hope it helpef
complete question:
A ship traveled for a total of 85 miles over the course of 5 hours. Heading west, the ship traveled at an average speed of 14 miles per hour, and heading north, it traveled at an average speed of 19 miles per hour. For how many hours was the ship heading north?
Answer:
The ship heading north traveled for 3 hours
Step-by-step explanation:
A ship travels for a total of 85 miles over the course of 5 hours journey. The speed of the journey can be calculated below.
speed = distance/time
total distance = 85
total time = 5 hours
speed = 85/5
speed = 17 miles/hr
West direction
Heading west the ship traveled at an average speed of 14 miles per hour. The speed can be represented for this journey as follows.
speed = distance/time
14 = dist/time
let
a = time traveled west
distance = 14a
North direction
speed = dist/time
19 = dist/time
time travel north = 5 - a
distance = 19(5 - a)
distance = 95 - 19a
Total distance traveled = 85 miles
85 = 14a + 95 - 19a
85 = -5a + 95
-10 = -5a
a = -10/-5
a = 2
The ship heading north will travel for 5 - 2 = 3 hours
as far as I can tell, is just a matter of going around the circle many or infinite times around.
so 6,31° is the first point, the next point will be one-go-around, 6, 31+360 => 6, 391°
then the next will be 6, 391+360 => 6, 751° and so on.
so we can say is (6, 31° ±360°n), n ∈ ℤ.
