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FromTheMoon [43]
2 years ago
11

Suppose that, for every lot of 100 computer chips a company produces, an average of 1.4 are defective. Another company buys many

lots of these chips at a time, from which one lot is selected randomly and tested for defects. If the tested lot contains more than three defects, the buyer will reject all the lots sent in that batch. What is the probability that the buyer will accept the lots?Assume that the defects per lot are Poisson distributed.Round your answer to 4 decimal places.The tolerance is +/- 0.0005.
Mathematics
1 answer:
Allisa [31]2 years ago
7 0

Answer:

0.1665

Step-by-step explanation:

Given that on an average 1.4 are defective per 100 computer chips

If the tested lot contains more than three defects, the buyer will reject all the lots sent in that batch.

Let X be the no of defective items in 100 chips

X is Poisson with mean =1.4

i.e. the probability that the buyer will accept the lots

=P(X\geq 3)\\\\=0.16651

Answer is 0.1665

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You work two jobs. You earn $11.90 per hour as a salesperson and $10.50 per hour stocking shelves. Your combined earnings this m
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178.50 = 11.90y + 10.50x ⇒ equation in standard form.

4 0
2 years ago
A school cafeteria sells milk at 25 cents per carton and salads at 45 cents each. one week the total sales for these items were
denis-greek [22]

solution:

Lets start with the most amount that could have been sold.......using guess and check, we can figure out that 290 salads could have been sold, while 8 cartons of milk would have been sold.

The least amount of salads that could have been sold were none.

so,

you have  0<s<290

at least none were sold, and at most 290 were sold

but I do believe you are missing part of the question


4 0
2 years ago
4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln
pochemuha

Answer:

No these these result do not differ at 95% confidence level  

Step-by-step explanation:

From the question we are told that

  The first concentrations is  c _1= 30.0 \ g/m^3

      The second concentrations is  c _2 = 52.9 \ g/m^3

  The first sample size is  n_1 =  32

    The second sample size is  n_2 =  32

   The  first standard deviation is \sigma_1 =  30.0

     The  first standard deviation is \sigma_1 =  29.0

The mean for  Turnpike is  \= x _1 = \frac{c_1}{n}  =  \frac{31.4}{32} = 0.98125

The mean for   Tunnel is  \= x _2 = \frac{c_2}{n}  =  \frac{52.9}{32} = 1.6531

The  null hypothesis is  H_o  :  \mu _1 - \mu_2  =  0

The  alternative hypothesis is  H_a  :  \mu _1 - \mu_2  \ne  0

Generally the test statistics is mathematically represented as

              t =  \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1}  +\frac{\sigma_2^2}{n_2} }}

         t =  \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32}  +\frac{29^2}{32} }}

        t = - 0.0899

Generally the degree of freedom is mathematically represented as

     df =  32+ 32 - 2

     df =  62

The  significance \alpha  is  evaluated as

      \alpha  =  (C - 100 )\%

=>   \alpha  =  (95 - 100 )\%

=>   \alpha  =0.05

The  critical value  is evaluated as

      t_c  =  2  *  t_{0.05 ,  62}

From the student t- distribution table  

        t_{0.05, 62} =  1.67

So

     t_c  =  2 * 1.67

=>  t_c  = 3.34

given that

       t_c  >  t we fail to reject the null hypothesis so  this mean that the result do  not differ

       

6 0
2 years ago
Henry is asked to find the exact value of cos 10pi/3. His steps are shown below.
nata0808 [166]

Answer:

<em>A) The reference angle should be </em><u><em>\frac{\pi }{3},</em></u><em> and the sign of the value should be </em><u><em>negative.</em></u>

Step-by-step explanation:

cos(\frac{10\pi }{3})

Remove full rotations of 2π until the angle is between 0 and 2\pi.

cos(\frac{4\pi }{3})

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because cosine is negative in the third quadrant.

 -cos(\frac{\pi }{3})

The exact value of cos(\frac{\pi }{3}) is \frac{1}{2}.

−\frac{1}{2}    

8 0
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tia_tia [17]

-\frac{10}{27}  hope this helps :)

8 0
2 years ago
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