Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
Answer:
D. 113
Step-by-step explanation:
If you take the other numbers and subtract each from the original 236, they all exceed the amount. So the answer would be 113.
Hey there,
So let's start off with one part of this equation
. . . 
would be 0.01.
So, we have 0.01 has our answer (so far).
Then we would do 7.1 × 0.01, this would give us
. . .
0.071.Your correct and final answer would be

Hope this helps you!
~Jurgen
18 pears subtract by 2 wich will equal 16 pears...
18-2=16