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krek1111 [17]
2 years ago
12

Ali picked 3 numbers out of a hat.

Mathematics
2 answers:
noname [10]2 years ago
6 0

Answer:

11, 17, 24

Step-by-step explanation:

Anna [14]2 years ago
4 0

Answer:11,17,24

Step-by-step explanation:

Lowest number=11

Range=13

Median=17

Range=highiest number - lowest number

13=highiest number -11

Highest number =13+11

Highest number=24

Ali's three numbers are 11,17,24

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445.5min=595²ft

Step-by-step explanation:

y=0.9x

y=0.9*495

y=445.5

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A bin of 5 transistors is known to contain 2 that are defective. The transistors are to be tested, one at a time, until the defe
xxMikexx [17]

Answer:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

Step-by-step explanation:

For the random variable N_1 we define the possible values for this variable on this case [1,2,3,4,5] . We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

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We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable N_1 like this:

P(N_1 = a) = \frac{5-a C 1}{5C2}

For the distribution of N_2 we need to take in count that we are finding a conditional distribution. N_2 given N_1 =a, for this case we see that N_2 \in [1,2,...,5-a], so then exist 5-a C 1 ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

P(N_2 =b | N_1 = a) = \frac{1}{5-a C 1}

And if we want to find the joint probability we just need to do this:

P(N_1 = a , N_2 = b) = P(N_2 = b | N_1 = a) P(N_1 =a)

And if we multiply the probabilities founded we got:

P(N_1 = a , N_2 = b)= \frac{1}{5-a C 1} * \frac{5-a C 1}{5C2} = \frac{1}{5C2}=\frac{1}{10}

8 0
1 year ago
A rocket leaves the surface of Earth at time t=0 and travels straight up from the surface. The height, in feet, of the rocket ab
erastovalidia [21]

Answer:

Remember that:

Speed = distance/time.

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if t0 = 200s

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if t0 = 400s

AS(400s) = (6250s - 1360s)/(500s - 300s) = 24.45 ft/s

So for the given options, t = 400s is the one where the velocity seems to be the biggest.

And this has a lot of sense, because while the distance between the values of time is constant (is always 100 seconds) we can see that the difference between consecutive values of y(t) is increasing.

Then we can conclude that the rocket is accelerating upwards, then as larger is the value of t, bigger will be the average velocity at that point.

3 0
2 years ago
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Answer:

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\frac{65}{100} *x=182\\\\\\65x=18200\\\\\\x=\frac{18200}{65} \\\\\\x=280

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