Question

On a coordinate plane, two parabolas open up. The solid-line parabola, labeled f of x, goes through (negative 2, 4), has a vertex at (0, 0), and goes through (2, 4). The dashed-line parabola, labeled g of x, goes through (3, 6), has a vertex at (5, 2), and goes through (7, 6). What is the equation of the translated function, g(x), if f(x) = x2? g(x) = (x + 5)2 + 2 g(x) = (x + 2)2 + 5 g(x) = (x – 2)2 + 5 g(x) = (x – 5)2 + 2

Answer 1

Answer:

g(x) = (x – 5)2 + 2

Step-by-step explanation:

D on edg

Answer 2

Answer:

Option 4.

Step-by-step explanation:

The vertex form of a parabola is

$g(x)=a(x-h)^2+k$                    ... (1)

where, a is a constant (h,k) is vertex.

The given function is

$f(x)=x^2$

The vertex of the function is (0,0) and it goes through (-2, 4) and (2, 4).

It is given that the vertex of function g(x) is at (5,2).

Substitute h=5 and k=2 in equation.

$g(x)=a(x-5)^2+2$

g(x) is passes through (3, 6).

$6=a(3-5)^2+2$             .... (2)

$6-2=4a$

$4=4a$

Divide both sides by 4.

$a=1$

Substitute a=1 in equation (2).

$g(x)=1(x-5)^2+2$

$g(x)=(x-5)^2+2$

The function g(x) is $g(x)=(x-5)^2+2$.

Therefor, the correct option is 4.