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zzz [600]
2 years ago
7

Julie will build a rectangular pen for her dog against a barn. A wall from the barn will form one side of the pen. She has 32 m

of fencing to form the other three sides. She plans to build the pen so that it has its maximum possible area. What will be the dimensions of Julie's pen? Enter your answers in the boxes.
Mathematics
2 answers:
Luden [163]2 years ago
5 0
8 m by the 6 m for your answer
emmainna [20.7K]2 years ago
5 0

Answer:

That person is wrong the right answer is

8m by 16m ( just took the test )

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Write a few sentences about different ways to show subtraction for a problem like 32 - 15
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32-15 first you would have to subtract the 2 and the 5 but you will have to borrow from the three make the 3 a 2 and make the 2 a 20 then  subtract 5 - 20 is 15 so carry the 1 to the 2 and bring down the 5 so now 1 - 2 is 1 + the 1 = 25 :)
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Ethan Makes $6 per hour mowing lawns and $7.50 per hour bagging groceries. last week, he made a total of $129. the difference be
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Let x be the number of hours of nagging groceries spent by Ethan. With this representation, the number of hours for moving lawns will be x + 10. The equation that would let us solve this item is,

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When comparing functions, such as Seth’s scenarios for travelling to school, will the function with the greatest initial value c
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It will depend whether is function time dependent or not.

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The endpoints of (line segment )AB are A(2, 2) and B(3, 8). (line segment ) AB is dilated by a scale factor of 3.5 with the orig
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The slope:
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The area of the conference table in Mr. Nathan’s office must be no more than 175 ft2. If the length of the table is 18 ft more t
Aleksandr [31]
Width = x
Length = x+18

Assuming the table is rectangular:
Area = x(x + 18)

Therefore:
x(x + 18) <span>≤ 175
x^2 + 18x </span><span>≤ 175

Using completing the square method:
x^2 + 18x + 81 </span><span>≤ 175 + 81
(x + 9)^2 </span><span>≤ 256
|x + 9| </span><span>≤ sqrt(256)
|x + 9| </span><span>≤ +-16
-16 </span>≤ x + 9 <span>≤ 16
</span>-16 - 9 ≤ x <span>≤ 16 - 9
</span>-25 ≤ x <span>≤ 7
</span><span>
But x > 0 (there are no negative measurements):
</span><span>
Therefore, the interval 0 < x </span><span>≤ 7 represents the possible widths.</span><span>

</span>
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