Answer:
This is a typical radioactive decay problem which uses the general form:
A = A0e^(-kt)
So, in the given equation, A0 = 192 and k = 0.015. We are to find the amount of substance left after t = 55 years. That would be represented by A. The solution is as follows:
A = 192e^(-0.015*55)
A = 84 mg
8,000 is 10 times as much as 800
From 0g to 494.7g are rejected as well as those heavier than 505.3grams.
You calculate this by subtracting and adding 5.3 to 500
Each angle has a sin, cos, and tan associated with it.
in a right angled triangle there are two other angles which each have ratios.
Answer:
0.02 inches per minute
Step-by-step explanation:
1 Week = 10080 minutes
Formaul: multiply the time value by 10080 to find the minutes in a week or do it the long way 60x24x7 = 10080
230/10080 = 0.02281746031 or 0.02 rounded to nearest hundert.
