Try this solution (note, the length of midsegment is (KG+FL)/2), all the details are in the attachment.
Answer is marked with green colour.
Answer:
a. The null hypothesis for this test is that the observed distribution is the same as uniform distribution
b. The degrees of freedom do you have for this test is 4
c. The calculated value of the test statistic is 9.250
Step-by-step explanation:
a. According to the given data we can conclude that the null hypothesis for this test is that the observed distribution is the same as uniform distribution.
b. In order to calculate the degrees of freedom do you have for this test we would have to make the following calculation:
degrees of freedom=k-1
degrees of freedom=5-1
degrees of freedom=4
c. In order to calculate the value of the test statistic first we have to calculate the frecuency expected as follows:
expected frecuency=total observed frecuency/total number of category
expected frecuency=1,000/5
expected frecuency=200
Hence, to calculate the value of the test statistic we have to calculate the following formula:
x∧2=∑(fo-fe)∧2/fe
=(185-200)∧2/200+(230-200)∧2/200+(215-200)∧2/200+(180-200)∧2+(190-200)∧2
=9.250
The calculated value of the test statistic is 9.250
Answer:An increase in visitors is correlated with an increase in sales.
Step-by-step explanation:
From the given scatter plot we can see that variables are positively correlated because they are moving in the same direction.
Since we know that the positive correlation is a relationship between two variables such that they increase or decrease together.
Since, the two variables given her is " number of visitors" and "Total sales"
Therefore, based on the given data it can be observed that "An increase in visitors is correlated with an increase in sales."
