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yan [13]
2 years ago
16

use the drop-down menus to describe the key aspects of the function f(x) = –x2 – 2x – 1. the vertex is the . the function is inc

reasing . the function is decreasing . the domain of the function is . the range of the function is .
Mathematics
2 answers:
timurjin [86]2 years ago
8 0

Answer:

The vertex of the parabola is the maximum value, i.e.,(-1,0). The function is increasing x<-1. the function is decreasing x>-1. the domain of the function is all real numbers. the range of the function is all real numbers less than or equal to 0.

Step-by-step explanation:

The given function is

f(x)=-x^2-2x-1

f(x)=-[x^2+2x+1]

f(x)=-(x+1)^2                 ....(1)

The general vertex form of the parabola is

f(x)=a(x-h)^2+k           .....(2)

Where, (h,k) is vertex and a is stretch factor.

On comparing (1) and (2), we get

a=-1

h=-1

k=0

The vertex of the parabola is (-1,0). Since a=-1<1 so it is a downward parabola.

The axis of symmetry is x=-1. So, before -1 the function is increasing and after -1 the function is decreasing.

The vertex of a downward parabola is the point of maxima. So, the rang of the function can not exceed 0.

Therefore the vertex of the parabola is the maximum value, i.e.,(-1,0). The function is increasing x<-1. the function is decreasing x>-1. the domain of the function is all real numbers. the range of the function is all real numbers less than or equal to 0.

Stolb23 [73]2 years ago
4 0

Answer:

The vertex is the .  maximum value

The function is increasing .  when x < -1

The function is decreasing . when x >-1

The domain of the function is . all real numbers

The range of the function is all numbers less than or equal to 0

Step-by-step explanation: edg

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CL 6-131. Solve each system using the method of your choice.
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System 1: The solution is (x, y) = (-4, 5)

System 2:  The solution is (x, y) = (\frac{11}{3}, -3)

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

2x + 3y = 7 ------ eqn 1

-3x - 5y = -13 --------- eqn 2

We can solve by elimination method

Multiply eqn 1 by 3

6x + 9y = 21 ------ eqn 3

Multiply eqn 2 by 2

-6x - 10y = -26 ------- eqn 4

Add eqn 3 and eqn 4

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y = 5

Substitute y = 5 in eqn 1

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2x = -8

x = -4

Thus the solution is (x, y) = (-4, 5)

<h3><em><u>Second system of equation is:</u></em></h3>

8 - y = 3x ------ eqn 1

2y + 3x = 5 ----- eqn 2

We can solve by susbtitution method

From given,

y = 8 - 3x ----- eqn 3

Substitute eqn 3 in eqn 2

2(8 - 3x) + 3x = 5

16 - 6x + 3x = 5

3x = 16 - 5

3x = 11

x = \frac{11}{3}

Substitute the above value of x in eqn 3

y = 8 - 3x

y = 8 - 3 \times \frac{11}{3}\\\\y = 8 - 11\\\\y = -3

Thus the solution is (x, y) = (\frac{11}{3}, -3)

4 0
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