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yan [13]
2 years ago
16

use the drop-down menus to describe the key aspects of the function f(x) = –x2 – 2x – 1. the vertex is the . the function is inc

reasing . the function is decreasing . the domain of the function is . the range of the function is .
Mathematics
2 answers:
timurjin [86]2 years ago
8 0

Answer:

The vertex of the parabola is the maximum value, i.e.,(-1,0). The function is increasing x<-1. the function is decreasing x>-1. the domain of the function is all real numbers. the range of the function is all real numbers less than or equal to 0.

Step-by-step explanation:

The given function is

f(x)=-x^2-2x-1

f(x)=-[x^2+2x+1]

f(x)=-(x+1)^2                 ....(1)

The general vertex form of the parabola is

f(x)=a(x-h)^2+k           .....(2)

Where, (h,k) is vertex and a is stretch factor.

On comparing (1) and (2), we get

a=-1

h=-1

k=0

The vertex of the parabola is (-1,0). Since a=-1<1 so it is a downward parabola.

The axis of symmetry is x=-1. So, before -1 the function is increasing and after -1 the function is decreasing.

The vertex of a downward parabola is the point of maxima. So, the rang of the function can not exceed 0.

Therefore the vertex of the parabola is the maximum value, i.e.,(-1,0). The function is increasing x<-1. the function is decreasing x>-1. the domain of the function is all real numbers. the range of the function is all real numbers less than or equal to 0.

Stolb23 [73]2 years ago
4 0

Answer:

The vertex is the .  maximum value

The function is increasing .  when x < -1

The function is decreasing . when x >-1

The domain of the function is . all real numbers

The range of the function is all numbers less than or equal to 0

Step-by-step explanation: edg

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Find the buoyant force of a rectangular solid of the given dimensions submerged in water so that the top side is parallel to the
11Alexandr11 [23.1K]

Answer:

Here is the continuation to the question ; The buoyant force is the difference between the fluid forces on the top and bottom of the solid. (The weight-density of water is 62.4 pounds per cubic foot.)

Hence, bouyant force is calculated as = 11980.8lb

Step-by-step explanation:

The steps are as shown in the attachment.

3 0
2 years ago
You and a friend have a hula hoop competition. you win 3 out of every 7 trials. your friend wins 5 more trials than you. how man
Ivenika [448]

Answer:

Total number of trials is 35.

Step-by-step explanation:

Given : Me and my friend have a hula hoop competition. I win 3 out of every 7 trials. My friend wins 5 more trials than me.  

To find : How many trials are in the competition?

Solution :

Probability of my winning is 3 out of 7 trials =\frac{3}{7}

and probability of my friend's winning is  =1-\frac{3}{7}=\frac{4}{7}  

Let there be n numbers of trials.

Therefore, my score after n trials =\frac{3n}{7}

and my friend's score after n trials   =\frac{4n}{7}

Now, the number of trials my friend won more than me is

\frac{4n}{7}-\frac{3n}{7}=\frac{n}{7}

We know, that my friend won 5 more trials than me so comparing the actual and given we get,

\frac{n}{7}=5\\n=7\times5=35

Therefore, total number of trials is 35.

We can also verify our answer by placing value of n,

After 35 trials I will win \frac{3\times 35}{7}=15 trials

and my friend will win \frac{4\times 35}{7}=20  trials.

Hence, my friend won 5 more trials than me.

3 0
2 years ago
Please answer all of them need this
VikaD [51]

First Question

For a better understanding of the solution provided here please find the first attached file which has the diagram of the the isosceles trapezoid.

We dropped perpendiculars from C and D to intersect AB at Q and P respectively.

As can be seen in \Delta BCQ, we can easily find the values of CQ and BQ.

Since, Sin(75^0)=\frac{CQ}{8}

\therefore CQ=8\times Sin(75^0)\approx 7.73 ft

In a similar manner we can find BQ as:

Cos(75^0)=\frac{BQ}{8}

BQ\approx2.07 ft

All these values can be found in the diagram attached.

Thus, because of the inherent symmetry of the isosceles trapezoid, PQ can be found as:

PQ=22-(AP+QB)=22-(2.07+2.07)=17.86

Let us now consider\Delta AQC

We can apply the Pythagorean Theorem here to find the length of the diagonal AC which is the hypotenuse of \Delta AQC.

AC=\sqrt{(AQ)^2+(QC)^2}=\sqrt{(AP+PQ)^2+(QC)^2}=\sqrt{(2.07+17.86)^2+(7.73)^2}\approx21.38 feet.

Thus, out of the given options, Option B is the closest and hence is the answer.

Second Question

For this question we can directly apply the formula for the area of a triangle using sines which is as:

Area=\frac{1}{2}(First Side)(Second Side)(Sine of the angle between the two sides)

Thus, from the given data,

Area=\frac{1}{2}\times 218.5\times 224.5\times sin(58.2^0)\approx20845 m^2

Therefore, Option D is the correct option.

Third Question

For this question we will apply the Sine Rule to the \Delta ABC given to us.

Thus, from the triangle we will have:

\frac{AB}{Sin(\angle C)}=\frac{BC}{Sin(\angle A)}

\frac{c}{Sin(\angle C)}=\frac{a}{Sin(\angle A)}

\frac{17}{Sin(25^0)}=\frac{a}{Sin(45^0)}

This gives a to be:

a\approx28.44

Which is not close to any of the given options.

Fourth Question

Please find the second attachment for a better understanding of the solution provided her.

As can be clearly seen from the attached diagram, we can apply the Cosine Rule here to find the return distance of the plane which is CA.

AC=\sqrt{(AB)^2+(BC)^2-2(AB)(BC)\times Cos(\angle B)}

\therefore AC=\sqrt{(172.20)^2+(111.64)^2-2(172.20)(111.64)\times Cos(177.29^0)}\approx283.8 miles.

Thus, Option D is the answer.





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