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hodyreva [135]
2 years ago
6

Suppose that we want to investigate whether curfews correlate with differences in grades for students in middle school. We selec

t a random sample of 81 middle school students. The variables are curfew (yes/no) and grade (a letter grade that represents the average grade across courses). Is there an association between grade and curfew? Or are these two variables independent? We use the data to conduct a chi-square test of independence at the 5% level. In this print-out, the observed count appears above the expected count in each cell. What can we conclude?

Mathematics
1 answer:
Anton [14]2 years ago
3 0

Answer:

Step-by-step explanation:

Hello!

Given the variables

X: Curfew of middle school students (Categorized Yes/No)

Y: Average grade of middle school students. (Categorized: A, B, C, and D)

The objective is to test if there is an association between both variables, you have to conduct a Chi-Square test of independence.

In the null hypothesis, you state that both variables are independent vs. the alternative hypothesis that the variables are dependent.

The hypotheses for this test are:

H₀: Pij= Pi. * P.j i= (1)Yes, (2)No; j= (1)A, (2)B, (3)C, (4)D

H₁: Te variables are not independent.

α: 0.05

X^2= sum\frac{(O_{ij}-E_{ij})^2}{E_{ij}} ~~X_{(r-1)*(c-1)}

Where

Oij is the observed frequency for the i-row and j-column

Eij is the expected frequency for the i-row and j-column

r= number of categories in the rows

c= number of categories in the columns

X^2_{H_0}= 1.4796703

p-value: 0.687

The p-value is greater than the significance level, so the decision is to not reject the null hypothesis. So using a 5% significance level, you can conclude that having a curfew and the average grades of middle schoolers are two independent variables.

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A gas can holds 10liters of gas. How many cans could we fill with 7 liters of gas?
telo118 [61]

Answer:

yes agas can hold 10 l of gas

Step-by-step explanation:

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6 0
1 year ago
Perry currently has $180 dollars and is spending $6 per day. Nick has no money but is earning $8 each day. After how many days w
Elan Coil [88]

12.857 days

Step-by-step explanation:

Since the number of days is passing the same for both Nick and Perry we can assign the unknown value (no. Of days) the same denotation of x

Therefore;

180 – 6x = 0 + 8x

180 = 8x + 6x

180 = 14x

X = 12.857

Learn More:

For more on calculating unknown values check out;

brainly.com/question/10578482

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4 0
2 years ago
Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as l
Goshia [24]
The answer:
<span>the upper and lower control limits (uclim and lclim) for mean formula is 

for the mean chart
uclim= x+A2xR
where x = sum(of the value)  / number of each value
and for 
lclim=</span>x+A2xR
<span>
R is the range such that R= Xmax - Xmin

in the case of the sample 1: S1
the data are: 
79.2    78.8   80.0   78.4   81.0

the mean is   x1 = (</span>79.2  +  78.8  +  80.0  + 78.4  + 81.0)  / 5=  79.48
<span>its range is    R 1= 81.0 -78.4 = 2.6

we can do the same method for finding the mean chart and range for all samples
</span>S2: x2=<span> 80.14  ,  R2=2.3
</span>S3: x3= 80.14  ,  R3=1.2
S4: x4= 79.60  ,  R4=1.7
S5: x5= 80.02  ,  R5=2.0
S6: x6=80.38   ,  R6=1.4
<span>
therefore the average value is   X= sum( x1+x2+...+x6) / 6 = 79.96
and R=sum(R1+R2+...+R6)/6=1.87
finally
range chart uclim =D4xR=3.95  and lclim is always equal to 0, because D3=0

we can say that the process is not in control.
       




</span>
3 0
2 years ago
Point b has coordinates (3,-4) and lies on the circle whose equation is x^2 + y^2= 25. If angle is drawn in a standard position
lakkis [162]
<span>Point B has coordinates (3,-4) and lies on the circle. Draw the perpendiculars from point B to the x-axis and y-axis. Denote the points of intersection with x-axis A and with y-axis C. Consider the right triangle ABO (O is the origin), by tha conditions data: AB=4 and AO=3, then by Pythagorean theorem:
</span>
<span>BO^2=AO^2+AB^2 \\ BO^2=3^2+4^2  \\ BO^2=9+16  \\ BO^2=25  \\ BO=5.
</span>
{Note, that BO is a radius of circle and it wasn't necessarily to use Pythagorean theorem to find BO}
<span>The sine of the angle BOA is</span>
\sin \angle BOA= \dfrac{AB}{BO} = \dfrac{4}{5} =0.8

Since point B is placed in the IV quadrant, the sine of the angle that is <span> drawn in a standard position with its terminal ray will be </span>
<span /><span>
</span><span>
</span>\sin \theta=-0.8 .





3 0
2 years ago
An automobile manufacturer sold 30,000 new cars, one to each of 30,000 customers, in a certain year. The manufacturer was intere
snow_lady [41]
A) In order to create a sampling plan, you need to follow the following 5 steps:
    1) Define the sample population: who are the customers you want to contact?
       The costumers who bought a new car on a certain year.
    2) Define the size of population: how many customers are you going to contact?
       Of the 30000 customers who bought a car, you want to contact 1000 customers.
    3) Define the contact options: how are you going to contact the customers?
       You have a list of names and addresses, therefore you can send a questionnaire via mail.
    4) Form a sampling frame: what is the time or contact frame to get in touch with your customers? 
       You will send the questionnaires and you will wait two months for the answer.
    5) Define the analysis method: is yours a qualitative or quantitative research?
     In your case, you want a quantitative research and therefore a probabilistic sampling.

B) The 32.5% probability refers to customers having issues with the power doors locks among the costumers who had problems, it does not consider the customers who did not have any problem or those who had problems after the first 5000 miles.

C) In order to find the probability of a power door lock problem if there have been problems within the first 5000 miles, we need to consider the whole sample:
P = 13 / 1000
   = 0.013

Therefore, 
N = <span>0.013 </span>× 30000
   = 390

Hence, the number of new cars sold that experienced a problem with the power door locks within the first 5000 miles will be 390.
         
4 0
2 years ago
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