Answer:

Step-by-step explanation:
For the random variable
we define the possible values for this variable on this case
. We know that we have 2 defective transistors so then we have 5C2 (where C means combinatory) ways to select or permute the transistors in order to detect the first defective:

We want the first detective transistor on the ath place, so then the first a-1 places are non defective transistors, so then we can define the probability for the random variable
like this:

For the distribution of
we need to take in count that we are finding a conditional distribution.
given
, for this case we see that
, so then exist
ways to reorder the remaining transistors. And if we want b additional steps to obtain a second defective transistor we have the following probability defined:

And if we want to find the joint probability we just need to do this:

And if we multiply the probabilities founded we got:

Given:
Annual salary average: $22,040
Annual Social security benefit: 42% of salary average
Monthly bill: $1,375
$22,040 x 42% = $9,256.80 per annum
$9,256.80 / 12 mos = $771.40 per month
$1,375 – 771.40 = $603.60
Since, Christina only receives $771.40 per month from her Social Security benefit, she has to take $603.60 from her savings each month to help pay her monthly bill of $1,375.
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Given data :
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
Where x is the number of terms ('x' is also written as 'n')
To find the 7th term (a₇):
We know that aₓ = -3/4 · aₓ₋₁
So,
a₃ = -3/4 · a₃₋₁
a₃ = -3/4 · a₂
9/16 = -3/4 · a₂
a₂ = 9/16 × -4/3
a₂ = -36/48
a₂ = -3/4
Again,
aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64
For a₅,
aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
a₅ = -3/4 · a₄
a₅ = -3/4 × -27/64
a₅ = 81/256
For a₆,
aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024
For a₇,
aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
Symmetric property is the correct term
Answer:
and
will be correct.
Explanation:
Given: two quadrilaterals having verticals P, N, O,M and S,T,V,U are congruent, where, OM is congruent or equal to TS and
.
in quadrilaterals NPOM and VUTS-
since, the condition 
and, side UV=side OM follow for the above quadrilateral. (According to the figure)
then we can say according to the property of quadrilateral, their corresponding sides must be congruent. so they are congruent.
similarly, these two conditions also follow in the case of
we can understand it by making the figures.