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erastovalidia [21]

2 years ago

14

Which statement justifies that 3x2 − 2x − 4 multiplied by 2x2 + x − 3 obeys the closure property of multiplication? The result 6

x4 − 2x2 + 12 has a degree of 4. The result 6x4 − 2x2 + 12 is a trinomial. The result 6x4 − x3 − 19x2 + 2x + 12 is a polynomial. The result 6x4 − x3 − 19x2 + 2x + 12 has a degree of 4.
I think it is B.

1 answer:

zalisa [80]2 years ago

4 0

We have been given two polynomials $3x^2-2x -4 \text{ and } 2x^2+x-3$

Let us first multiply these polynomials.

$(3x^2 - 2x - 4)(2x^2 + x - 3)\\
\\
=3x^2(2x^2 + x - 3) -2x(2x^2 + x - 3)-4(2x^2 + x - 3)\\
\\
=6 x^4 - x^3 - 19 x^2 + 2 x + 12$

Now, we know that polynomials follows closure property of multiplication.

It means that when we multiply two polynomials, the result will be a polynomial.

Since, when we multiplied the given polynomials, we got $6 x^4 - x^3 - 19 x^2 + 2 x + 12$ which is a polynomial.

Therefore, the correct option is

The result $6 x^4 - x^3 - 19 x^2 + 2 x + 12$ is a polynomial.

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Identify the segment bisector of JK

nordsb [41]

Answer:

A segment whose length is 9 units.

Step-by-step explanation:

A segment whose length is 9 units.

All we have is a bisection that divides equally segment JK in two parts. And M is the Midpoint what reassures us that JM=MK, so plugging in:

3x+15=8x+25

3x-8x=25-15

-5x=10

5x=-10

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Ahat [919]

Answer:

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Step-by-step explanation:

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1 year ago

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ohaa [14]

Geometric mean is just the two numbers multiplied together under a square root sign
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2 years ago

Read 2 more answers

Angela and Neil are going to the movies. They each bought a medium popcorn, and Neil got a small soft drink. Angela had a $5 gif

bagirrra123 [75]

Let us assume the cost of a soft drink = x dollars
Value of the gift certificate that Angela had = $5
Cost of the movie ticket = $10
Cost of a medium popcorn = $5.50
Then
27.90 + 5 = 2(10) + 2(5.50) + x
32.90 = 20 + 11 + x
32.90 = 31 + x
x = 1.90 dollars

From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or $1.90.

6 0

2 years ago

A piece of paper is to display ~128~ 128 space, 128, space square inches of text. If there are to be one-inch margins on both si

Grace [21]

Answer:

The dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches

Step-by-step explanation:

We have that:

$Area = 128$

Let the dimension of the paper be x and y;

Such that:

$Length = x$

$Width = y$

So:

$Area = x * y$

Substitute 128 for Area

$128 = x * y$

Make x the subject

$x = \frac{128}{y}$

When 1 inch margin is at top and bottom

The length becomes:

$Length = x + 1 + 1$

$Length = x + 2$

When 2 inch margin is at both sides

The width becomes:

$Width = y + 2 + 2$

$Width = y + 4$

The New Area (A) is then calculated as:

$A = (x + 2) * (y + 4)$

Substitute $\frac{128}{y}$ for x

$A = (\frac{128}{y} + 2) * (y + 4)$

Open Brackets

$A = 128 + \frac{512}{y} + 2y + 8$

Collect Like Terms

$A = \frac{512}{y} + 2y + 8+128$

$A = \frac{512}{y} + 2y + 136$

$A= 512y^{-1} + 2y + 136$

To calculate the smallest possible value of y, we have to apply calculus.

Different A with respect to y

$A' = -512y^{-2} + 2$

Set

$A' = 0$

This gives:

$0 = -512y^{-2} + 2$

Collect Like Terms

$512y^{-2} = 2$

Multiply through by $y^2$

$y^2 * 512y^{-2} = 2 * y^2$

$512 = 2y^2$

Divide through by 2

$256=y^2$

Take square roots of both sides

$\sqrt{256=y^2$

$16=y$

$y = 16$

Recall that:

$x = \frac{128}{y}$

$x = \frac{128}{16}$

$x = 8$

Recall that the new dimensions are:

$Length = x + 2$

$Width = y + 4$

So:

$Length = 8 + 2$

$Length = 10$

$Width = 16 + 4$

$Width = 20$

To double-check;

Differentiate A'

$A' = -512y^{-2} + 2$

$A" = -2 * -512y^{-3}$

$A" = 1024y^{-3}$

$A" = \frac{1024}{y^3}$

The above value is:

$A" = \frac{1024}{y^3} > 0$

This means that the calculated values are at minimum.

<em>Hence, the dimensions of the smallest piece that can be used are: 10 by 20 and the area is 200 square inches</em>

3 0

1 year ago