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Scilla [17]
2 years ago
6

Paul wants to add new mulch to the top of all five garden beds. the new mulch will be 10 centimetres (cm) deep. about how much n

ew mulch in cubic meters will paul need for this job? there is 3 beds across the top 4m x 3m and 2 across the bottom 5m x 3m
Mathematics
2 answers:
DedPeter [7]2 years ago
7 0

Answer:

Dimension of a Rectangular Box = 4 m × 3 m

Dimension of Second Rectangular box =5 m × 3m

→Mulch should be added to these two rectangular boxes having height 10 cm=0.01 m.Because 1 meter=100 cm.

Volume of 3 Cuboids having dimension , 4m × 3m × 0.01 m

           =3 ×Length × Breadth × Height

           =3× 4m × 3m × 0.01 m

           =0.36 m³

Volume of 2 Cuboids having dimension , 5m × 3m × 0.01 m

          =2× 5m × 3m × 0.01 m

           = 0.30 m³

Total volume or Amount of the Mulch that is to be added to Rectangular Boxes

                   =0.36 m³ +0.30 m³

                 =0.66 m³

ladessa [460]2 years ago
4 0
(4*4*10)*3
160*3=480
(5*3*10)*2
150*2=300
480+300=780 cub. meters
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Answer:

b + d = 180°, a = d and a = c

Step-by-step explanation:

With the figure we can see that the only way for them to be parallel is that the angles are similar with their counterpart, for example that a = d. a = c will show that all angles are equal in order to be m and n parallel. Finally b + d = 180° shows that the only way for this to be true is that m and n are parallel.

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Here is  the correct computation of the question given.

Find the coefficient of variation for each of the two sets of data, then compare the variation. Round results to one decimal place. Listed below are the systolic blood pressures (in mm Hg) for a sample of men aged 20-29 and for a sample of men aged 60-69.

Men aged 20-29:      117      122     129      118     131      123

Men aged 60-69:      130     153      141      125    164     139

Group of answer choices

a)

Men aged 20-29: 4.8%

Men aged 60-69: 10.6%

There is substantially more variation in blood pressures of the men aged 60-69.

b)

Men aged 20-29: 4.4%

Men aged 60-69: 8.3%

There is substantially more variation in blood pressures of the men aged 60-69.

c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

d)

Men aged 20-29: 7.6%

Men aged 60-69: 4.7%

There is more variation in blood pressures of the men aged 20-29.

Answer:

(c)

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

Step-by-step explanation:

From the given question:

The coefficient of variation can be determined by the relation:

coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

We will need to determine the coefficient of variation both men age 20 - 29 and men age 60 -69

To start with;

The coefficient of men age 20 -29

Let's first find the mean and standard deviation before we can do that ;

SO .

Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

Mean = \frac{117+122+129+118+131+123}{6}

Mean = \dfrac{740}{6}

Mean = 123.33

Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

Standard deviation =\sqrt{\dfrac{(117-123.33)^2+(122-123.33)^2+...+(123-123.33)^2}{(6-1)} }

Standard deviation  = \sqrt{\dfrac{161.3334}{5}}

Standard deviation = \sqrt{32.2667}

Standard deviation = 5.68

The coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

coefficient \ of  \ variation = \dfrac{5.68}{123.33}*100

Coefficient of variation = 4.6% for men age 20 -29

For men age 60-69 now;

Mean = \dfrac{\sum \limits^{n}_{i-1}x_i}{n}

Mean = \frac{   130 +    153    +  141  +    125 +   164  +   139}{6}

Mean = \dfrac{852}{6}

Mean = 142

Standard deviation  = \sqrt{\dfrac{\sum (x_i- \bar x)^2}{(n-1)} }

Standard deviation =\sqrt{\dfrac{(130-142)^2+(153-142)^2+...+(139-142)^2}{(6-1)} }

Standard deviation  = \sqrt{\dfrac{1048}{5}}

Standard deviation = \sqrt{209.6}

Standard deviation = 14.48

The coefficient \ of  \ variation = \dfrac{standard \ deviation}{mean}*100

coefficient \ of  \ variation = \dfrac{14.48}{142}*100

Coefficient of variation = 10.2% for men age 60 - 69

Thus; Option C is correct.

Men aged 20-29: 4.6%

Men aged 60-69: 10.2 %

There is substantially more variation in blood pressures of the men aged 60-69.

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