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aivan3 [116]
2 years ago
10

Triangle QRS is translated 7 units right, then rotated 90 degrees clockwise about the origin. The vertices of triangle Q"R"S" ar

e Q"(6, -1), R"(0, -1), and S"(0, -7). Determine the coordinates of triangle QRS
Mathematics
1 answer:
Goryan [66]2 years ago
7 0

Answer:

Q (-6.6), R (-6.0), S (0.0)

Step-by-step explanation:

In the exercise we are asked to find the original coordinates with the given transforms, which means that we must apply the inverse of the indicated transformations.

Original coordinates: Q "(6, -1), R" (0, -1) and S "(0, -7)

When turning 90 ° counterclockwise, since we want the opposite, the following change occurs (the axes and the sign are inverted):

Q '(1.6), R' (1.0), S '(7.0)

Now we have to move to the left by 7 units, because it is the opposite of the right, only on the x axis, 7 is subtracted

Q (-6.6), R (-6.0), S (0.0)

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The distance from the tether ball pole to the edge of the circle is 5 feet what is the circumference of the circle ?
ololo11 [35]

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31.416

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The 30 members of a choir are trying to raise at least $1,500 to cover travel costs to a singing camp. They already have $600. W
ryzh [129]
The choir members need $1500, but they have $600.  Therefore, they need $1500-$600=$900 more.

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0.17 =<br> 0.1090 =<br> ,0.050 =
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Step-by-step explanation:

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8 0
1 year ago
Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =
FromTheMoon [43]

Answer:

Here is the question attached with.

m\angle CEA =90 \ (deg)

m\angle BEF=135\ (deg)

\angle CEF is a straight line.

\angle AEF is a right angled triangle.

Options 1,4,5,6 are correct answers.

Step-by-step explanation:

⇒As \ ray\ AE  is ⊥FEC so it will forms right angled triangle then m\angle CEA =90\ (deg).

⇒Measure of \angle BEF =135\ (deg) as \angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg) as \angle AEB is the bisector of \angle AEC,meaning that  \angle AEB is half of \angle AEC so  \angle AEB = 45\ (deg).

⇒\angle CEF is a straight line as the angles measure over it is 180\ (deg).

⇒Measure of \angle AEF = 90\ (deg) from linear pair concept.

As \angle CEA + \angle AEF = 180\ (deg),plugging the values of  m\angle CEA =90\ (deg) we have \angle AEF = 90\ (deg) .

The other two options are false as:

  • m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225

       it is exceeding 180\ (deg) whereas \angle CEF is a              

      straight line.

  • And m\angle CEB=2(m\angle CEA) is not true.

     As \angle CEA = 90\ (deg) and \angle CEB=45\ (deg)

So we have total 4 answers.

The correct options are 1,4,5,6.

5 0
2 years ago
Read 2 more answers
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