I don’t know if I’m wrong but Yeah I Think It’s C
Answer:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition
Step-by-step explanation:
Answer:
A) Swing arcs on both sides to intersect the first two arcs created.
Step-by-step explanation:
Bisecting a segment is cutting a line into two equal parts with a line bisector.
The steps involved are;
- Placing a compass on one endpoint
- Opening the compass to a width larger than half of the segment
- Swinging an arc on either side of the segment
- While maintaining the same width, place the compass on the other endpoint
- Swing arcs on both sides of the segment to intersect the first two arcs created
- Using a ruler placed at the points of intersection of the arcs, draw the line bisector.
Sasha was now at step four.
The probability p of an orangecandy is 0.2. The sample size = 100.
The mean is given by:

The standard deviation is given by:

The answers are: Mean = 20. Standard deviation = 4.
Answer:
369 students have taken a course in either calculus or discrete mathematics
Step-by-step explanation:
I am going to build the Venn's diagram of these values.
I am going to say that:
A is the number of students who have taken a course in calculus.
B is the number of students who have taken a course in discrete mathematics.
We have that:

In which a is the number of students who have taken a course in calculus but not in discrete mathematics and
is the number of students who have taken a course in both calculus and discrete mathematics.
By the same logic, we have that:

188 who have taken courses in both calculus and discrete mathematics.
This means that 
212 who have taken a course in discrete mathematics
This means that 
345 students at a college who have taken a course in calculus
This means that 
How many students have taken a course in either calculus or discrete mathematics

369 students have taken a course in either calculus or discrete mathematics