Question

A fruit stand has to decide what to charge for their produce. They need \$5.30$5.30dollar sign, 5, point, 30 for 111 apple and 111 orange. They also need \$7.30$7.30dollar sign, 7, point, 30 for 111 apple and 222 oranges. We put this information into a system of linear equations.

Answer 1

Answer:

111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)

Step-by-step explanation:

Let the price of 111 apples be $x and the price of 111 oranges be $y.

1. 111 apples and 111 oranges cost $5.30, thus

x+y=5.30

2. 111 apples and 222 oranges cost $7.30, then

x+2y=7.30

Subtract the first equation from the second:

x+2y-x-y=7.30-5.30

y=2

Substitute it into the first equation:

x+2=5.30

x=3.30

111 apples cost $3.30 and 111 oranges cost $2 (1 apple costs nearly $0.03 and 1 orange costs nearly $0.02)

Answer 2

Answer:

3.30 for apple and 2.00 for an orange

Step-by-step explanation: