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Vinil7 [7]
2 years ago
8

Lola needs to sign 96 invitations. Using a stopwatch that measures time to tenths of a second, it takes Lola 5.3 seconds to sign

her full name. Going by the accuracy of the stopwatch, which is the most accurate determination for the number of seconds Lola needs to sign all 96 invitations?
508 seconds
510 seconds
509 seconds
508.8 seconds
Mathematics
2 answers:
ikadub [295]2 years ago
8 0

Answer:

508.8 seconds

Step-by-step explanation:

The most accurate determination mathematically is to assume that Lola will maintain an average of 5.3 seconds per signature as she signs all 96 invitations.

Therefore, multiply the time it takes her to sign each invitation (5.3 seconds) by the total number of invitations there are (96 invitations) to get the projected total amount of time that it will take Lola to sign all 96 invitations:96\cdot 5.3=\boxed{508.8\text{ seconds}}

Harrizon [31]2 years ago
3 0

Answer:

508.8

Step-by-step explanation:

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1.5

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5/8 + 7/8= 1.5 or 1  1/2

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The product of three integers is −5. Determine all of the possible values for the three factors.
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Explain why f(x)= 1/(x-x3)^3 is not continuous at x = 3.
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Answer: Option b.

Step-by-step explanation:

 1. You have the function f(x)=\frac{1}{(x-3)^{3}} given in the problem above.

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3. The value x=3 makes the denominator of the function f(x) equal to zero. Therefore you can conclude that the function shown in the problem is not defined at x=3.

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Of all the weld failures in a certain assembly, 85% of them occur in the weld metal itself, and the remaining 15% occur in the b
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b.) 0.6477

c.) 0.0388

d.) 3

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Step-by-step explanation:

Forming a binomial Probability distribution

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Probability of success for Weld metal failure = 85%

Probability of success for base metal failure = 15%

We use the probabilit distribution formula of combination to solve the problem.

P(x=r) = nCr * p^r * q^n-r

a.) if exactly 5 are base metal failures, then p = 15 and our solution becomes:

P(x=5) = 20C5 * 0.15^5 * 0.85^15

P(x=5) = 0.1028

b.) probability that fewer than 4 are base metal failure= P(x=0) + P(x=1) + P(x=2) + P(x=3)

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P(x=2) = 20C2 * 0.15² * 0.85^18 = 0.2293

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P(x=0) = 0.0388

d.) mean of base metal failures = np = 20*0.15 = 3

e.) standard deviation of base metal failures = √np(1-p)

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