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2 years ago

Complete the following multiplication exercises.

2 answers:

4 0

43x7=301
12x9=108
10x6=60
9x7=63
7x5=35
6x3=18
0x8=8
30x3=90
11x8=88
73x2=219
83x5=415
16x8=128
392x7=2,744
29x4=116
761x9=6,849
4,829x6=28,974
12x7=84
25,500x4=102,000

tamaranim1 [39]2 years ago

4 0

To solve these equations, you should understand that multiplication simple means adding a number (the multiplicand) to itself a specified number of times. For example 3 x 2, means adding 3 to itself 2times "3+3 = 6" , another example 5 x 3, means adding 5 to itself 3times "5+5+5 = 15"

So,

43x7=301 ....add 43 to itself 7times

12x9=108

10x6=60

9x7=63

7x5=35

6x3=18

0x8=0

30x3=90

11x8=88

73x2=219

83x5=415

16x8=128

392x7=2,744

29x4=116

761x9=6,849

4,829x6=28,974

12x7=84

25,500x4=102,000

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To solve this question, I did an equation:
0.75x + 1.20y = 120
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2 years ago

A simple random sample of 100 concert tickets was drawn from a normal population. The mean and standard deviation of the sample

alexandr402 [8]

Answer:

We accept the null hypothesis and the population mean is $120.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 100

Sample mean, $\bar{x}$ = $120

Alpha, α = 0.01

Sample standard deviation, s = $25

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 125\\H_A: \mu \neq 125$

We use two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = -2.0$

p-value one tail= 0.024

p-value two tail= 0.048

Conclusion:

Since the p-value for two tailed test is greater than the significance level, we fail to reject the null hypothesis and accept it.

Thus, the population mean is $120.

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2 years ago

help me the area of a rectangular roof of a doghouse is 756 square inches. the length of the roof is 108 inches. how many inches

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$A=L*w \\ A=756 \ square \ inches \\L=108 \ inches \\ \\ 108*w=756 =>w=756:108 \\ \\ w=7 \ inches$

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2 years ago

Read 2 more answers

An element with mass 730 grams decays by 28.8% per minute. How much of the element is remaining after 10 minutes, to the nearest

trasher [3.6K]

$\bf \qquad \textit{Amount for Exponential Decay}\\\\
A=P(1 - r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{initial amount}\to &730\\
r=rate\to 28.8\%\to \frac{28.8}{100}\to &0.288\\
t=\textit{elapsed time}\to &10\\
\end{cases}
\\\\\\
A=730(1-0.288)^{10}\implies A=730(0.712)^{10}$