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2 years ago

Complete the following multiplication exercises.

2 answers:

4 0

43x7=301
12x9=108
10x6=60
9x7=63
7x5=35
6x3=18
0x8=8
30x3=90
11x8=88
73x2=219
83x5=415
16x8=128
392x7=2,744
29x4=116
761x9=6,849
4,829x6=28,974
12x7=84
25,500x4=102,000

tamaranim1 [39]2 years ago

4 0

To solve these equations, you should understand that multiplication simple means adding a number (the multiplicand) to itself a specified number of times. For example 3 x 2, means adding 3 to itself 2times "3+3 = 6" , another example 5 x 3, means adding 5 to itself 3times "5+5+5 = 15"

So,

43x7=301 ....add 43 to itself 7times

12x9=108

10x6=60

9x7=63

7x5=35

6x3=18

0x8=0

30x3=90

11x8=88

73x2=219

83x5=415

16x8=128

392x7=2,744

29x4=116

761x9=6,849

4,829x6=28,974

12x7=84

25,500x4=102,000

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What number should be added to both sides of the equation to complete the square? x2 + 3x = 6 (StartFraction 3 Over 2 EndFractio

Alex73 [517]

Answer:

$\frac{9}{4}$

Step-by-step explanation:

Given

x² + 3x = 6

To complete the square

add ( half the coefficient of the x- term )² to both sides

x² + 2( $\frac{3}{2}$ )x + ( $\frac{3}{2}$ )² = 6 + ( $\frac{3}{2}$ )²

The number added to both sides is ( $\frac{3}{2}$ )² = $\frac{9}{4}$

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2 years ago

Read 2 more answers

Find all the zeros of the equation 12x^2-64=-x^4

Natalija [7]

Answer: all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

Step-by-step explanation:

Since we have given that

$12x^2-64=-x^4\\\\x^4+12x^2-64=0$

We need to find the zeroes of the above equation.

So, we will use "Split the middle terms" :

$x^4+12x^2-64=0\\\\x^4+16x^2-4x^2-64=0\\\\x^2(x^2-16)-4(x^2-16)=0\\\\(x^2-4)(x^2-16)=0\\\\x^2-4=0\ or\ x^2-16=0\\\\\text{ "Using }a^2-b^2=(a+b)(a-b)"\\\\x^2-4=x^2-2^2=(x-2)(x+2)\\\\x^2-16=x^2-4^2=(x+4)(x-4)$

So, all the zeroes of the above equation will be

(x-4)(x+4)(x-2)(x+2)

7 0

2 years ago

The pucks used by the National Hockey League for ice hockey must weigh between and ounces. Suppose the weights of pucks produced

Dahasolnce [82]

Answer:

$P(5.5$

And we can find this probability using the normal standard distribution or excel and we got:

$P(-2.769$

Step-by-step explanation:

For this case we assume the following complete question: "The pucks used by the National Hockey League for ice hockey must weigh between 5.5 and 6 ounces. Suppose the weights of pucks produced at a factory are normally distributed with a mean of 5.86 ounces and a standard deviation of 0.13ounces. What percentage of the pucks produced at this factory cannot be used by the National Hockey League? Round your answer to two decimal places. "

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

$X \sim N(5.86,0.13)$