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Artyom0805 [142]
1 year ago
7

M&M plain candies come in various colors. According to the M&M/Mars Department of Consumer Affairs, the distribution of

colors for plain M&M candies is as follows.
Color Purple Yellow Red Orange Green Blue Brown
Percentage 21% 18% 18% 8% 8% 6% 21%
Suppose you have a large bag of plain M&M candies and you choose one candy at random.
(a) Find P(green candy or blue candy).

Are these outcomes mutually exclusive? Why?
Yes. Choosing a green and blue M&M is possible.
No. Choosing a green and blue M&M is possible.
Yes. Choosing a green and blue M&M is not possible.
No. Choosing a green and blue M&M is not possible.


(b) Find P(yellow candy or red candy).

Are these outcomes mutually exclusive? Why?
Yes. Choosing a yellow and red M&M is possible.
Yes. Choosing a yellow and red M&M is not possible.
No. Choosing a yellow and red M&M is possible.
No. Choosing a yellow and red M&M is not possible.


(c) Find P(not purple candy).
Mathematics
1 answer:
UkoKoshka [18]1 year ago
8 0
Since the Σ( of all colors )= 100%,  OR 1, then:

a) P(GREEN ∪ BLUEU) = P(G) + P(BL) = 8%+6% = 14% or 0.14

Since we have to choose ONE candy and only ONE candy at random, then tey are mutually exclusive: No. Choosing a green and blue M&M is possible

b) P(YELLOW ∪ RED) = P(Y) + P(R) = 18%+18% = 36% or 0.36
SAME ANSWER AS BEFORE: mutually exclusive

c) P(NOT PURPLE), Let's calculate 1st, the probability of having a PURPLE:
P(PURPLE) = 21% or 0.21
And the Probability of NOT having a PURPLE is 1-0.21 = 0.79
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The perimeter of a rectangle is 13cm and its width is 11/4. find its length.
enyata [817]
Perimeter = 2 length + 2 width

P = 2(l) + 2(11/4)

13 = 2l +2* \frac{11}{4}

13 = 2l + \frac{2}{1} * \frac{11}{4}

13 = 2l + \frac{22}{4}     (subtract 22/4 from each side)

13 -\frac{22}{4} = 2l

13 -\frac{11}{2} = 2l

\frac{26}{2}  -\frac{11}{2} = 2l

\frac{15}{2}} = 2l

7.5 = 2l    (divide each side by 2)

7.5 ÷ 2 = l

3.75 = l

The answer is 3.75 or 3 \frac{3}{4}


6 0
1 year ago
Solve for x: one over eight (8x + 15) = 24
svetlana [45]
1/8 ( 8x + 15)= 24

x + 1 7/8= 24

x= 24 - 1 7/8

x= 22 1/8

The answer is none of them.
4 0
2 years ago
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Frank wants to build a garden with the dimensions below.
dexar [7]
Given:
Length = x + x + 3 = 2x + 3
Width = 2 + x 

Area = length * width 
91 ft² = (2x + 3) (2+x)
91 = 4x + 2x² + 6 + 3x
0 = 2x² + 7x + 6 - 91
0 = 2x² + 7x - 85

(2x + 17) ( x - 5)

x = -17/2 or  x = 5

Let x = 5 ; 

length = 2x + 3 = 2(5) + 3 = 13
width = 2 + x = 2 + 5 = 7

 Area = 13 x 7 = 91

Perimeter = 2(length + width)
Perimeter = 2(13 + 7)
Perimeter = 2(20)
Perimeter = 20 feet of fencing
7 0
1 year ago
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Phil received a prize of xxx dollars from a poker tournament. The tournament cost him 100100100 dollars to enter.
nikitadnepr [17]

Answer:

$(x-100)

Step-by-step explanation:

  • Phil entered the poker tournament with $100.
  • He received a price of $x.

His net winnings from the tournament will be the price minus the entry fee.

Therefore:

Phil's net winnings=$(x-100)

8 0
2 years ago
According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg
Sati [7]

Answer:

a) Mean blood pressure for people in China.

b) 38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c) 71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d) 8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e) Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg

f) 157.44mmHg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If X is two standard deviations from the mean or more, it is considered unusual.

In this question:

\mu = 128, \sigma = 23

a.) State the random variable.

Mean blood pressure for people in China.

b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.

This is 1 subtracted by the pvalue of Z when X = 135.

Z = \frac{X - \mu}{\sigma}

Z = \frac{135 - 128}{23}

Z = 0.3

Z = 0.3 has a pvalue of 0.6179

1 - 0.6179 = 0.3821

38.21% probability that a person in China has blood pressure of 135 mmHg or more.

c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.

This is the pvalue of Z when X = 141.

Z = \frac{X - \mu}{\sigma}

Z = \frac{141 - 128}{23}

Z = 0.565

Z = 0.565 has a pvalue of 0.7140

71.30% probability that a person in China has blood pressure of 141 mmHg or less.

d.)Find the probability that a person in China has blood pressure between 120 and 125 mmHg.

This is the pvalue of Z when X = 125 subtracted by the pvalue of Z when X = 120. So

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 128}{23}

Z = -0.13

Z = -0.13 has a pvalue of 0.4483

X = 120

Z = \frac{X - \mu}{\sigma}

Z = \frac{120 - 128}{23}

Z = -0.35

Z = -0.35 has a pvalue of 0.3632

0.4483 - 0.3632 = 0.0851

8.51% probability that a person in China has blood pressure between 120 and 125 mmHg.

e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?

From b), when X = 135, Z = 0.3

Since Z when X = 135 is less than two standard deviations from the mean, it is not unusual for a person in China to have a blood pressure of 135 mmHg.

f.) What blood pressure do 90% of all people in China have less than?

This is the 90th percentile, which is X when Z has a pvalue of 0.28. So X when Z = 1.28. Then

X = 120

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{X - 128}{23}

X - 128 = 1.28*23

X = 157.44

So

157.44mmHg

6 0
1 year ago
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