V=basearea times 1/3 times height
basearea=64π m2
hmm, they try to make it difficult

basearea=circle=pir^2
pir^2=64pi
divide by pi
r^2=64
sqrt
r=9

h is 4 les than 3 time r
h=-4+3(8)
h=-4+24
h=20

v=1/3*64pi*20=1280pi/3 m^3=1350.4

C

4 0

2 years ago

The product of two consecutive integers is 420. An equation is written in standard form to solve for the smaller integer by fact

alex41 [277]

Answer:

X * (X +1) = 420

X^2 + X = 420

X^2 + X -420 = 0

X = 20

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

If r=[x,y,z] and r0=[x0,y0,z0], describe the set of all points (x,y,z) such that Ir-r0I =1.

sdas [7]

Answer:

The points (x,y,z) that respond to Ir-r0I =1, are all that describes the form $(x-x_0)^2+(y-y_0)^2+(z-z_0)^2=1$ with:

-1+x₀<x<1+x₀

-1+y₀<y<1+y₀

-1+z₀<z<1+z₀

Step-by-step explanation:

All points required in this problem came from applying the definition of modulus of a vector:

Ir-r0I =1.

$|(x,y,z)-(x_{0},y_{0},z_{0})|=|(x-x_{0},y-y_{0},z-z_{0})|=\sqrt{(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2}=1\\(x-x_{0})^2+(y-y_{0})^2+(z-z_{0})^2=1^2=1$

5 0

2 years ago