Write the inequalities that are given by the :
<span>x: the number of batches of muffins
y: the number of batches of cakes
</span>Each batch of muffin requires 7 liters of milk and each batch of cakes
require 4 liters of milk.
=> liters of milk use = 7x + 4y
<span>Tania
has 56 liters of milk.=> 7x + 4y ≤ 56
Which means that the amount of muffins and cakes made are limited by the availability of 56 liter of milk.
The inequality 7x + 4y ≤ 56 is graphed by drawing the line 7x + 4y = 56 and shading the region below that line.
The line 7x + 4y = 56 has these x and y intercepts:
y-intercept: x =0 => 4y = 56 => y = 56/4 => 14 => point (0,14)
x-intercept => y = 0 => 7x = 56 => x = 56/7= 8 => point (8,0)
So, the line passes through the poins (0,8) and (14,0) and the solution region is below that line.
Also, you know that x and y are restricted to be positive or zero =>
x ≥ 0
y ≥ 0.
So, the solution region is restricted to the first quadrant.
That implies that the answer is:
</span><span>
Line joining ordered pairs 0, 14 and 8, 0. Shade the portion of the graph below this line which lies within the first quadrant
</span>
Answer:
<h2>Option A is the answer(here the answer is calculated taking the whole value, without approximating it to a nearest value)</h2>
Step-by-step explanation:
Annual interest rate is 2.75%. Hence, the monthly interest rate is 
The amount will be compounded 
times.
Every month they deposits $500.
In the first month that deposited $500 will be compounded 240 times.
It will be ![500\times [1 + \frac{2.75}{1200} ]^{240}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D)
In the second month $500 will be deposited again, this time it will be compounded 239 times.
It will give ![500\times [1 + \frac{2.75}{1200} ]^{239}](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D)
Hence, the total after 20 years will be ![500\times [1 + \frac{2.75}{1200} ]^{240} + 500\times [1 + \frac{2.75}{1200} ]^{239} + ........+ 500\times [1 + \frac{2.75}{1200} ]^{1} = 160110.6741](https://tex.z-dn.net/?f=500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B240%7D%20%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B239%7D%20%2B%20........%2B%20500%5Ctimes%20%5B1%20%2B%20%5Cfrac%7B2.75%7D%7B1200%7D%20%5D%5E%7B1%7D%20%3D%20160110.6741)
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Answer:
expression a
Step-by-step explanation:
The given expression is 15+0.25(d−1).
let suppose,
15 = a
0.25(d−1) = b
we get a + b
It clearly indicates the given expression is sum of two entities, we can exclude option b and option d.
Now we are left with option a and c, for that we have to evaluate the term b
b = 0.25(d−1) <u>that is the additional amount after d days</u>
Therefore, expression a is correct.
1) You included neihter what Ramesh says nor the statements, then I can you tell some facts about the pattern.
2) The sequence is: 2401, 343, 49, 7, and 1.
3) The first term is 2401
4) The sequence is a decreasing geometric one.
5) The ratio is found dividing two consecutive terms (the second by the first, or the third by the second, or the fourth by the third, or the fifth by fourth):
1/7 = 7 / 49 = 49 / 343 = 343 / 2401.
So, the ratio is 1/7
6) The sum of that sequence is 2401 + 343 + 49 + 7 + 1 = 2801
