Solution:
Consider the Given Isosceles Triangle
Considering the Possibilities
Case 1. When two equal angles are of 70°
Let the third angle be x.
Keeping in mind , that sum of Interior angles of Triangle is 180°.
70° + 70° + x= 180°
140° +x= 180°
x= 180°- 140°
x= 40°
Case 2:
When an angle measures 70°, and two equal angles measure x°.
Keeping the same property of triangle in mind, that is sum of interior angles of triangle is 180°.
70° + x° + x° = 180°
⇒ 70° + 2 x° = 180°
⇒ 2 x° = 180° - 70°
⇒ 2 x° = 110°
Dividing both sides by 2, we get
x= 55°
Answer:A. on edge
Step-by-step explanation:
Just took the quiz.
Determine the slope of line AB
m = 5
Determine the slope of the lines from the options
First option: y = 5x + 3, the slope is 5
Second option: y = (1/5)x + 3, the slope is 1/5
Third option: y = -5x + 3, the slope is -5
Fourth option: y = (-1/5)x + 3, the slope is -1/5
Parallel lines are similar in the slope. So the line which is parallel to line AB must have the slope of 5.
The answer is first option.
Answer:
48 cm
Step-by-step explanation:
Given:
Distance of rod from the wall = 45 cm
Distance of rod from the light = 15 cm
Length of rod = 12 cm
We can see that <DAM and <BAF are equal
Also, <DMA and <BFM are equal because they are corresponding angles
To find the length of the shadow, let's take the equation
Where.:
DM = ½ of length of the rod = ½*12 = 6
A.F = 15 + 45 = 60 cm
AM = 15 cm
Therefore,
Cross multiplying, we have:
15 * B.F = 60 * 6
15 * B.F = 360
BF = 24 cm
The shadow on the wall =
2 * BF
= 2 * 24
= 48 cm
The shadow on the wall is 48 cm
Answer:
m∠QPM=43°
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
m∠NPQ=m∠MPN+m∠MPQ
we have
m∠NPQ=(9x-25)°
m∠MPN=(4x+12)°
m∠MPQ=(3x-5)°
substitute the given values and solve for x
(9x-25)°=(4x+12)°+(3x-5)°
(9x-25)°=(7x+7)°
9x-7x=25+7
2x=32
x=16
Find the measure of angle QPM
Remember that
m∠QPM=m∠MPQ
m∠MPQ=(3x-5)°
substitute the value of x
m∠MPQ=(3(16)-5)=43°
therefore
m∠QPM=43°
