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kari74 [83]
2 years ago
8

A lottery sells 1000 tickets at $1 apiece. There is one winner who receives $100, and 5 second place winners who receive $50 eac

h. What is the expected value of a ticket? In your final answer, include the necessary calculations.
Mathematics
1 answer:
DaniilM [7]2 years ago
5 0
Chance of winning $100 = 1/1000 
<span>chance of winning $50 = 5/1000 = 1/200 </span>
<span>cost of ticket = -1 </span>
<span>E[x] = 100* 1/1000 + 50* 1/200 -1 </span>
<span>= 0.1 + 0.25 - 1 = -0.65 

Hope this helps</span>
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Each beehives on Larson’s honey farm usually produces 85lbs of honey per year. About how many pounds of honey will 10,000 hives
schepotkina [342]

If one of Larson's beehives produces 85lbs of honey, you need to multiply it with the given number of hives, which is 10,000.


So: 85 * 10,000 = 850,000lbs

8 0
2 years ago
Which sets of numbers contain whole numbers? Check all that apply. Negative 2 and StartFraction 5 Over 6 EndFraction, negative 5
Zigmanuir [339]

Answer:

The whole numbers are 0 and 79.

Step-by-step explanation:

The numbers provided are as follows:

-2\frac{5}{6},\ -54,\ -4,\ -57,\ -89,\ 79,\ \frac{6}{9},\ \\\\-19\frac{2}{3},\ \frac{2}{4},\ 0,\ \frac{2}{7},\ -3,\ -2, -7,\ -8,\ \\\\\frac{1}{8},\ -\frac{4}{8},\ 1\frac{3}{8},\ -\frac{7}{8}

Whole numbers are a set of natural positive numbers and 0. This set basically consists of counting discrete numbers.

Such as: 0, 1, 2, 3, 4, 5....

From the provided set of numbers the whole numbers are:

S = {79 and 0}

Thus, the whole numbers are 0 and 79.

8 0
2 years ago
Rationalize the denominator of $\frac{2}{3\sqrt{5} + 2\sqrt{11}}$ and write your answer in the form $\displaystyle \frac{A\sqrt{
vlada-n [284]

Answer:

<h2>19</h2>

Step-by-step explanation:

Given the surdic expression \frac{2}{3\sqrt{5} + 2\sqrt{11}}\\, to rationalize the expression, we will have to multiply the numerator and denominator of the expression by the conjugate of the denominator as shown;

= \frac{2}{3\sqrt{5} + 2\sqrt{11}} * \frac{3\sqrt{5} - 2\sqrt{11}}{3\sqrt{5} - 2\sqrt{11}}\\\\= \frac{2(3\sqrt{5} - 2\sqrt{11})}{(3\sqrt{5} + 2\sqrt{11})(3\sqrt{5} - 2\sqrt{11})}\\\\= \frac{6\sqrt{5} - 4\sqrt{11}  }{9\sqrt{25}+6\sqrt{55}- 6\sqrt{55}-4\sqrt{121}  } \\\\=  \frac{6\sqrt{5} - 4\sqrt{11}  }{9(5)-4(11)  }\\\\=  \frac{6\sqrt{5} - 4\sqrt{11}  }{45-44  }\\\\= \frac{6\sqrt{5} - 4\sqrt{11}  }{1}

Comparing the result \frac{6\sqrt{5} - 4\sqrt{11}  }{1} with the expression \frac{A\sqrt{B} + C\sqrt{D}}{E}, it can be seen that A = 6, B = 5, C = -4, D = 11 and E = 1

A+B+C+D+E = 6+5+(-4)+11+1

A+B+C+D+E = 11-4+12

A+B+C+D+E = 19

Hence the value of A+B+C+D+E is 19

4 0
2 years ago
Suha is going to buy 150 envelopes.
Katyanochek1 [597]

Suha should buy 150 envelopes from shop 1 because the cost in shop 1 is 0.06 less shop 2.

<u>Step-by-step explanation</u>:

Total number of envelopes = 150

<u>The cost of envelopes :</u>

  • Pack of 25 envelopes in shop 1 = 3.49
  • Pack of 10 envelopes in shop 2 = 2.10
  • Buy 2 packs get 1 pack free in shop 2.

<u>Shop 1 :</u>

The number of packs to buy 150 envelopes = 150 /25 = 6 packs

The total cost to buy 6 packs = 6 × 3.49 = 20.94

The cost of 150 envelopes in shop 1 is 20.94

<u>Shop 2 :</u>

The number of packs to buy 150 envelopes = 150 /10 = 15 packs

  • For each 2 packs you get 1 pack free.
  • 10 packs + 5 free packs = 15 packs

The total cost to buy 10 packs = 10 × 2.10 = 21

The cost of 150 envelopes in shop 2 is 21

The difference between shop 2 and shop 1 = 21 - 20.94 = 0.06

Therefore, the cost in shop 1 is 0.06 less than shop 2. So, Suha should buy 150 envelopes from shop 1.

8 0
2 years ago
Read 2 more answers
What are the solutions of the equation x4 + 3x2 + 2 = 0? Use u substitution to solve.
Julli [10]

ANSWER

x =  \: x =  \pm \:  \sqrt{2} i \: or \: x =  \pm \: i

EXPLANATION

{x}^{4}  + 3 {x}^{2}  + 2 = 0

{ ({x}^{2}) }^{2}  + 3( {x}^{2})  + 2 = 0

Let

u  =  {x}^{2}

Then the equation becomes:

{u}^{2}  + 3u + 2 = 0

{u}^{2}  + 3u + 2 = 0

{u}^{2}  + 2u +u +  2 = 0

Factor:

{u}(u + 2)+ 1(u +  2) = 0

(u + 1)(u +  2) = 0

u =  - 1

or

u =  - 2

This implies that

{x}^{2}  =  - 1 \implies \: x =  \pm \: i

or

{x}^{2}  =  - 2 \implies \: x =  \pm \:  \sqrt{2} i

3 0
2 years ago
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