Every day, the number of network blackouts has a distribution (probability mass function)
1 answer:
Expected Mean, E(X), is obtained by multiplying each pair of 
and its 
and add up the answers
E(X) = (0×0.7) + (1×0.2) + (2×0.1) = 0.4
The formula to calculate the variance, Var(X), is given by E(X)² - (E(X))²
E(X²) = (0²×0.7) + (1²×0.2) + (2²×0.1) = 0+0.2+0.4 = 0.6
(E(X))² = (0.4)² = 0.16
Var(X) = 0.6 - 0.16 = 0.44
Translating these answers into the context we have
E(Y) = 0.4×500 = $200
Var(Y) = $110
E(X) = (0×0.7) + (1×0.2) + (2×0.1) = 0.4
The formula to calculate the variance, Var(X), is given by E(X)² - (E(X))²
E(X²) = (0²×0.7) + (1²×0.2) + (2²×0.1) = 0+0.2+0.4 = 0.6
(E(X))² = (0.4)² = 0.16
Var(X) = 0.6 - 0.16 = 0.44
Translating these answers into the context we have
E(Y) = 0.4×500 = $200
Var(Y) = $110
You might be interested in
Answer:
Hi! This is the answer for part C, or finding the factors.
Step-by-step explanation:
Checked by my teacher. hope this part helps. Will post the rest soon.
Answer:
No. James didn't have enough ticket takers to process the average number of patrons hat usually attend the events.
He need to hire 2 more ticket taker (i.e 20 ticket takers) in order to process the average number of patrons hat usually attend the events.
Step-by-step explanation:
Given:
Average amount of patron per event= 7000
Each ticket taker can process = 350
Number of ticket takers hired = 18
We need to find the whether he hire enough to process the average number of patrons that usually attend the events.
Solution:
We will find the Average amount of patron ticket takers can process.
Now we can say that
Average amount of patron ticket takers can process is equal to Each ticket taker can process multiplied by Number of ticket takers hired.
framing in equation form we get;
Average amount of patron ticket takers can process =
Hence With the required hires James cannot fully process the patrons usually attending the event.
To find how many ticket takers required we will divide average number of patrons with Each ticket taker can process.
framing in equation form we get;
ticket takers required =
hence In order t process the the average number of patrons that usually attend the events James will require 20 ticket takers.