<span> x(4-k)=p
[x(4-k)=p]/x
4-k=p/x
-4 = -4
-k=p/x-4
k=4-p/x
</span>
Answer:
x can take any value and are viable in this situation if and only if it is a positive number
Step-by-step explanation:
We know that the area of a rectangle is given by:
A = x * y
So if we replace we have:
12 ≤ x * y ≤ 36
We divide by y, and we have:
12 / y ≤ x ≤ 36 / y
Which means that the value of x depends on y, that is to say if y is worth 1, the inequality would be:
12 ≤ x ≤ 36
In the event that y is equal to 2:
12/2 ≤ x ≤ 36/2
6 ≤ x ≤ 18
Which means, that depending on y, x can take any value and are viable in this situation if and only if it is a positive number.
Well the sides of these 2 quadrilaterals are proportional to each other , so you would have to find the scale factor of the 2 then see which sides have already proportional pairs , then multiply *or / to find the last one .
Answer: D. 11.7 ft
Answer:
we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years
Step-by-step explanation:
Given that in a study on the fertility of married women conducted by Martin O’Connell and Carolyn C. Rogers for the Census Bureau in 1979, two groups of childless wives aged 25 to 29 were selected at random, and each was asked if she eventually planned to have a child. One group was selected from among wives married less than two years and the other from among wives married five years.
Let X be the group married less than 2 years and Y less than 5 years
X Y Total
Sample size 300 300 600
Favouring 240 288 528
p 0.8 0.96 0.88

p difference = -0.16
Std error for difference = 
Test statistic = p difference/std error=-6.03
p value <0.000001
Since p is less than alpha 0.05 we cannot conclude hat the proportion of wives married less than two years who planned to have children is significantly higher than the proportion of wives married five years