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kirill [66]
2 years ago
7

I need to know how to solve part b please!

Mathematics
1 answer:
Margaret [11]2 years ago
3 0

Xavier spent $84 on supplies (so this is an expense we will make only once), and then he will spend one more dollar for each canvas. So, his total expense for p paintings will be

84+p

Similarly, he will get 8 dollars for each painting, so he will earn

8p

dollars if he will sell p paintings.

In order to break even, earnings and costs must be equal:

84+p=8p

Subtract p from both sides:

84=7p

Divide both sides by 7:

12=p

So, he has to sell at least 12 paintings to break even.

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URGENT<br>Which of the following is the graph of y=0.5sec (x+pi/3)-2?
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Answer:

See attachment.

Step-by-step explanation:

The given function is

y=0.5\sec(x+\frac{\pi}{3})-2

This is the graph of y=\sec(x) that is shifted down 2 units and shifted to the left \frac{\pi}{3} units.

When x=0, y=0.5\sec(0+\frac{\pi}{3})-2

y=0.5\sec(\frac{\pi}{3})-2

y=1-2=-1

The y-intercept is -1.

The correct choice is shown in the attachment

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2 years ago
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qwelly [4]

Step-by-step explanation:

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1. Divded 35 by 14 and u get 0.4

2

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Paula weighed 65.5 kilograms before she started training she as lost 3500grams how much does she weigh
Alborosie
Hello!

We have the following data:

Paula weight (before training) = 65.5 kg
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Using V = lwh, what is an expression for the volume of the following prism? The dimensions of a prism are shown. The height is S
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<h2>Explanation:</h2><h2></h2>

We know that the volume of a prism is defined by:

V=lwh \\ \\ \\ Where: \\ \\ l:length \\ \\ w:width \\ \\ h:height \\ \\ \\ l=\frac{d-2}{3d-9} \\ \\ w=\frac{4}{d-4} \\ \\ h=\frac{2d-6}{2d-4}

Substituting values:

V=\left(\frac{d-2}{3d-9}\right)\left(\frac{4}{d-4}\right)\left(\frac{2d-6}{2d-4}\right) \\ \\ \\ Simplifying: \\ \\ V=\frac{d-2}{3d-9}\cdot \frac{4}{d-4}\cdot \frac{d-3}{d-2} \\ \\ V=\frac{\left(d-2\right)\cdot \:4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)\left(d-2\right)} \\ \\ V=\frac{4\left(d-3\right)}{\left(3d-9\right)\left(d-4\right)} \\ \\ V=\frac{4\left(d-3\right)}{3\left(d-3\right)\left(d-4\right)}

Finally: \\ \\  \boxed{V=\frac{4}{3\left(d-4\right)}}

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