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zloy xaker [14]
2 years ago
9

The difference between two numbers is 9. The first number plus twice the other number is 27. Find the two numbers.

Mathematics
1 answer:
umka21 [38]2 years ago
3 0

Answer:

The two numbers are <u>15</u> and <u>6</u>.

Step-by-step explanation:

Given:

The difference between two numbers is 9.

The first number plus twice the other number is 27.

Now, to find the two numbers.

Let the first number be x.

And the other number be y.

So, the difference between two numbers is 9.

x-y=9

x=9+y    ............(1)

As, given the first number plus twice the other number is 27.

According to question:

x+2y=27

Substituting the value of x from equation (1):

(9+y)+2y=27\\9+y+2y=27\\9+3y=27

<em>Subtracting both sides by 9 we get:</em>

3y=18

<em>Dividing both sides by 3 we get:</em>

y=6.

The other number = 6.

Now, substituting the value of y in equation (1):

x=9+y\\x=9+6\\x=15.

The first number = 15.

Therefore, the two numbers are 15 and 6.

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The left side  

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True

Step-by-step explanation:


4 0
2 years ago
Evaluate \dfrac14c+3d
Crank

Answer:  \frac{45}{2}

Step-by-step explanation:

<h3> The exercise is: " Evaluate \frac{1}{4}c + 3d when c = 6 and   d = 7</h3>

Given the following expression:

 \frac{1}{4}c + 3d

You can follow these steps in order to evaluate it:

 1. Substitute c = 6 and   d = 7 into the expression provided in the exercise:

  \frac{1}{4}(6) + 3(7)

2. Solve the multiplications. Remember that:

 \frac{a}{b}*\frac{c}{d}=\frac{ac}{bd}

Then:

 =\frac{6}{4} +21

3. Reduce the fraction. Notice that the numerator 6 and the denomiantor 4 can be both divided by 2. Then:

=\frac{3}{2} +21

4. Solve the addition:

=\frac{3}{2} +\frac{21}{1}

 Since the number 21 has a denominator 1, the Least Common Denominator is:

LCD=2

Then, the sum is:

=\frac{3+42}{2}=\frac{45}{2}

5 0
2 years ago
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Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Bas
disa [49]

Answer:

Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot?

2 a b c squared (RootIndex 3 StartRoot 4 a squared b cubed c EndRoot)

4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)

8 a cubed b cubed c Superscript 4 Baseline (RootIndex 3 StartRoot b c EndRoot)

8 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)

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2 years ago
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In ΔGHI, the measure of ∠I=90°, IG = 6.8 feet, and HI = 2.6 feet. Find the measure of ∠G to the nearest degree.
Luda [366]

Answer:

\angle G=20.8\approx 21^{\circ}

Step-by-step explanation:

Given: In ΔGHI, \angle I=90°, IG = 6.8 feet, and HI = 2.6 feet

To find: \angle G

Solution:

Trigonometry defines relationship between the sides and angles of the triangle.

For any angle \theta,

tan\theta = side opposite to \theta/side adjacent to \theta

In ΔGHI,

tan G=\frac{HI}{GI}

Put HI=2.6  \,\,feet\,,\,GI=6.8\,\,feet

So,

tan G=\frac{2.6}{6.8}=0.38

Therefore, \angle G=20.8\approx 21^{\circ}

Download pptx
3 0
2 years ago
A teacher wants to see if a new unit on factoring is helping students learn. She has five randomly selected students take a pre-
sergiy2304 [10]

Answer:

The <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

Step-by-step explanation:

The confidence interval formula for mean difference for a paired data is as follows:

CI=\bar x_{d}\pm t_{\alpha/2, (n-1)}\times \frac{s_{d}}{\sqrt{n}}

Here,

\bar x_{d} = sample mean of the difference,

s_{d} = sample standard deviation of the difference,

<em>n </em>= sample size (both samples are of same size).

t_{\alpha/2, (n-1)} = critical value of <em>t</em>

(<em>n</em> - 1) = degrees of freedom

The information provided is:

<em>n</em> = 5

Confidence level = 95%

The critical value of <em>t</em> is:

t_{\alpha/2, (n-1)}=t_{0.05/2, (5-1)}

               =t_{0.025, 4}

               =2.776

*Use a <em>t</em>-table for the critical value of <em>t</em>.

Thus, the <em>t</em>-value used for the 95% confidence interval of paired data is 2.776.

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