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ArbitrLikvidat [17]
2 years ago
7

Explaining Factored Form The trinomial x2 + bx – c has factors of (x + m)(x – n), where m, n, and b are positive. What is the re

lationship between the values of m and n? Explain.
Mathematics
2 answers:
ycow [4]2 years ago
8 0

Sample Response: The value of m must be greater than the value of n. When you multiply the binomials, the middle term is the result of combining the outside and inside products. So, bx = –nx + mx, or bx = (–n + m)x. This means that b = –n + m. When adding numbers with opposite signs, you subtract their absolute values, and keep the sign of the number having the larger absolute value. Since b is positive, m must have the larger absolute value.

(on the assignment)

Sliva [168]2 years ago
6 0
The value of m<span> must be greater than the value of</span><span> n</span><span>. When you multiply the binomials, the middle term is the result of combining the outside and inside products. So, </span>bx<span> = –</span>nx<span> + </span>mx<span>, or </span>bx<span> = (–</span>n<span> + </span>m)x<span>. This means that </span>b<span> = –</span>n<span> + </span>m<span>. When adding numbers with opposite signs, you subtract their absolute values, and keep the sign of the number having the larger absolute value. Since </span>b<span> is positive, </span>m<span>must have the larger absolute value.</span>
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Answer:

P(Bag is Defective) = 0.0167

Step-by-step explanation:

Line 1 produces twice as many bags as line 2. Let x be the number of bags produced by line 2.

No. of bags produced by line 2 = x

No. of bags produced by line 1 = 2x

Probability that the bag has been produced by line 1 can be written as:

P(Line 1) = No. of bags produced by line 1/Total no. of bags

             = 2x/(x+2x)

             = 2x/3x

P(Line 1) = 2/3. Similarly,

P(Line 2) = x/3x

P(Line 2) = 1/3

1% bags produced by line 1 are defective so the probability of line 1 producing a defective bag is:

P(Defective|Line 1) = 0.01

3% of bags from line 2 are defective, so:

P(Defective|Line 2) = 0.03

b. The probability that the chosen bag is defective can be calculated through the conditional probability formula:

P(A|B) = P(A∩B)/P(B)

<u>P(A∩B) = P(A|B)*P(B)</u>

The chosen defective bag can be either from line 1 or from line 2. So, the probability that the chosen bag is defective is:

P(Bag is Defective) = P(Defective and from Line 1) + P(Defective and from Line 2)

                                = P(D∩Line 1) + P(D∩Line 2)

                                = P(Defective|Line 1)*P(Line 1) + P(Defective|Line 2)*P(Line 2)

                                = (0.01)*(2/3) + (0.03)(1/3)

P(Bag is Defective) = 0.0167

7 0
2 years ago
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