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yuradex [85]
1 year ago
8

Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Bas

eline EndRoot??
Mathematics
2 answers:
disa [49]1 year ago
6 0

Answer:

Which expression is equivalent to RootIndex 3 StartRoot 64 a Superscript 6 Baseline b Superscript 7 Baseline c Superscript 9 Baseline EndRoot?

2 a b c squared (RootIndex 3 StartRoot 4 a squared b cubed c EndRoot)

4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)

8 a cubed b cubed c Superscript 4 Baseline (RootIndex 3 StartRoot b c EndRoot)

8 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)

mel-nik [20]1 year ago
5 0

4 a squared b squared c cubed (RootIndex 3 StartRoot b EndRoot)

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What is -1 2/3 + 5/6​
Monica [59]

Answer:

-5/6

Step-by-step explanation:

-1 2/3=-5/3

-5/3+5/6=-10/6+5/6=-5/6

5 0
2 years ago
Read 2 more answers
A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
butalik [34]

Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

8 0
2 years ago
Determine the value of (tangent of 88 degrees, 22 minutes, and 45 seconds). In this case, minutes are 1/60 of a degree and secon
mariarad [96]

Answer:

  c.  35.34015106

Step-by-step explanation:

As with many problems of this nature, you only need to get close to be able to choose the correct answer. 22 minutes 45 seconds is just slightly less than 1/2 degree (30 minutes), so the tangent value will be just slightly less than tan(88.5°) ≈ 38. The appropriate choice is 35.34015106.

If you need confirmation, you can find tan(88°) ≈ 29, so you know the answer will be between 29 and 38.

__

The above has to do with strategies for choosing answers on multiple-choice problems. Below, we will work the problem.

The angle is (in degrees) ...

  88 + 22/60 +45/3600 = 88 + (22·60 +45)/3600 = 88 +1365/3600

  ≈ 88.3791666... (repeating) . . . . degrees

A calculator tells you the tangent of that is ...

  tan(88.3791666...°) ≈ 35.3401510614

Many calculators will round that to 10 digits, as in the answer above. Others can give a value correct to 32 digits. Spreadsheet values will often be correct to 15 or 16 digits.

4 0
1 year ago
The volume inside of a sphere is V=4πr33 where r is the radius of the sphere. Your group has been asked to rearrange the formula
Semmy [17]

Answer:

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

Step-by-step explanation:

Given:

Volume of inside of the sphere is given as

V=\frac{4}{3} \pi r^{3}

where r is the radius of the sphere

To Find:

r =?

Solution:

We have

V=\frac{4}{3} \pi r^{3}   ......Given

3\times V=4\pi r^{3} \\\\\therefore r^{3}=\frac{3V}{4\pi } \\\\\therefore r=\sqrt[3]{\frac{3V}{4\pi }} \textrm{which is the expression for r}

Therefore,

r=\sqrt[3]{\frac{3V}{4\pi }}

is the required r

5 0
1 year ago
Carla investe € 8000 in due quote diverse. Sul- la prima parte del capitale guadagna il 3%, sulla parte restante il 2%. Sapendo
MA_775_DIABLO [31]

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