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KonstantinChe [14]
1 year ago
14

How many meatballs are required for a party of 25 adults and 5 children

Mathematics
1 answer:
scoray [572]1 year ago
5 0
Should be 30 meatballs. This is because there are 25 adults and 5 kids. 25+5 = 30. That is the least amount you need. However, most people try to provide at least 2 servings per person. So that would be 60 meatballs. That way each person has two meatballs. Hope this helps, if so please give brainliest:-)
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Given the function f(x) = 3x, find the value of f−1(81).
Shalnov [3]
Given the function f (x) = 3x, find the value of f-1 (81).
 For this case, the first thing you should do is rewrite the function.
 We have then:
 y = 3 ^ x
 From here, we clear the value of x:
 log3 (y) = log3 (3 ^ x)
 log3 (y) = x
 Then, we rewrite the function again:
 f (x) ^ - 1 = log3 (x)
 Now, we evaluate the inverse function for x = 81:
 f (81) ^ - 1 = log3 (81)
 f (x) ^ - 1 = 4
 Answer:
 the value of f-1 (81) is: 
 f (x) ^ - 1 = 4
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The scale of the map is 1/8 inch to 12 miles.the Mitchell family drove from lee springs to boothville in 3 3/4.What was their ap
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What is the average speed of a runner if he ran 2 1/3 of a mile in 20 minutes?
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7 MPH because 2 1/3
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The potential energy, P, in a spring is represented using the formula P = kx2. Lupe uses an equivalent equation, which is solved
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So, kx^{2} =P and

k=\frac{P}{x^{2} }

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Let x represent number of bracelets and y represent number of necklaces.

We have been given that a jeweler made 7 more necklaces than bracelets. This means that number of necklaces will be x+7. We can represent this information in an equation as:

y=x+7...(1)

We have been given that the amount of gold in each bracelet is 6 grams, so amount used for x bracelets would be 6x grams.

We are also told that the amount of gold in each necklace is 16 grams, so amount used for y necklaces would be 16y grams.

Since the jeweler used 178 grams of gold, so we will equate the amount of gold used in x bracelets and y necklaces with 178 as:

6x+16y=178...(2)

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6x+16y=178...(2)

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