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Svetradugi [14.3K]

2 years ago

8

Circle Z is shown. Line segments Z T, Z U, and Z V are radii of the circle. Line segment U X goes through point X and is a diame

ter. Line segment W Y goes from one side to the opposite side and intersects line segment U X at point S. Line segment W X is a secant. Angle X W X is 42 degrees, angle W S Y is 100 degrees, and angle T Z U is 79 degrees. Complete the statements about circle Z. A central angle, such as angle of circle Z, is an angle whose vertex is and whose sides are radii of the circle. Angle is not a central angle of circle Z. The degree measure of an arc is the degree measure of the central angle that intercepts it. The measure of is degrees.

2 answers:

tatiyna2 years ago

7 0

Answer:

uzv

the center of the circle

WSX

equal to

79

Step-by-step explanation:

on edginuity

Sauron [17]2 years ago

6 0

Answer:

He is correct

Step-by-step explanation:

You might be interested in

Suppose that a high school marching band has 125 members. Of these 125 band members, 41 are seniors, 24 play the trumpet, and 10

Alborosie

Answer:

<em>The probability is 42%</em>

Step-by-step explanation:

<u>Conditional Probability</u>

It's the probability of the occurrence of an event B knowing that an event A has already occurred and A and B are related (not independent).

If P(A) is the probability of occurrence of A, $P(A\cap B)$ is the probability of both events to occur, and P(B|A) is the required probability occurrence of B:

$\displaystyle P(B|A)=\frac{P(A\cap B)}{P(A)}$

We know a high school marching band has 125 members, from which 41 are seniors (event B), 24 play the trumpet (event A), and 10 are seniors who play the trumpet.

The probability that a randomly selected band member plays the trumpet is

$\displaystyle P(A)=\frac{24}{125}$

The probability that he or she has both attributes is

$\displaystyle P(A\cap B)=\frac{10}{125}$

Thus, the required conditional probability is

$\displaystyle P(B|A)=\frac{\frac{10}{125}}{\frac{24}{125}}$

$\displaystyle P(B|A)=\frac{10}{24}=\frac{5}{12}=0.42$

The probability is 42%

5 0

2 years ago

According to a Los Angeles Times study of more than 1 million medical dispatches from 2007 to 2012, the 911 response time for me

Reil [10]

Answer:

a) $\bar X=10.65$

$Median =\frac{10.7+10.7}{2}=10.7$

$Mode= 10.7$

b) $Range = 11.8-8.3=3.5$

$s= 0.948$

c) $IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

Step-by-step explanation:

We have the following data:

11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2

Part a

We can calculate the sample mean with the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

And if we replace we got: $\bar X=10.65$

For the median we need to sort the values on increasing order and we have:

8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8

Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:

$Median =\frac{10.7+10.7}{2}=10.7$

The mode would be the most repeated value on this case:

$Mode= 10.7$

Part b

The range is defined as $Range =Max-Min$ and if we replace we got:

$Range = 11.8-8.3=3.5$

We can calculate the standard deviation with the following formula:

$s= sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

And if we replace we got:

$s= 0.948$

Part c

For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.

We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and $Q_1= \frac{10.6+10.7}{2}=10.55$

And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got $Q_3 = \frac{10.9+11.2}{2}=11.05$

Then we can find the IQR like this:

$IQR = Q_3 -Q_1 = 11.05-10.55=0.5$

And we can find the usual limits with:

$Lower = Q_1 -1.5 IQR = 10.55 -1.5*0.5=9.8$

$Upperer = Q_3 +1.5 IQR = 10.55 +1.5*0.5=11.3$

And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.

Part d

The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.

And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.

6 0

2 years ago

Yuson must complete 210 min of community service. She does 30 min each day. Which linear equation represents the number of minut

Misha Larkins [42]

Answer:

$y=-30x+210$

Step-by-step explanation:

Let

x -----> the number of days

y ----> the number of minutes Yuson has left

we know that

The linear equation in slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-coordinate of the y-intercept (initial value)

In this problem we have

The slope is equal to

$m=-30\frac{min}{day}$ ----> is negative because is a decreasing function

$b=210\ min$ ----> initial value

substitute the values

$y=-30x+210$

3 0

2 years ago

A battery with 20% of its full capacity is connected to a charger. Every minute that passes, an additional 5% of its capacity is

Masja [62]

Answer:

Step-by-step explanation:

y = 5x + 20

Start at (0, 20).

Then plot a point at (1, 25).

The line should be going through points (2, 30), (3, 35), (4, 40), (5, 45), etc.

For every time the x number goes up, the y number goes up 5 times for the 5%.

3 0

2 years ago

Read 2 more answers

Jamie and owen joined a monthly walking challenge at their youth center. jamie has already walked 120 minutes and plans to walk

sertanlavr [38]

Y=20x+120
y=30x

30x=20x+120
30x-20x=120
10x=120
x=12 days

y=30x
y=30(12)
y=360 minutes

3 0

2 years ago

Read 2 more answers